从ArrayList中删除偶数 [英] Remove even numbers from an ArrayList

问题描述

我必须创建一个有ArrayList的方法;我需要从这个ArrayList中删除偶数。我已经写了代码，但有一个逻辑错误，我不能确定。

I have to create a method which has an ArrayList; I need to remove even numbers from this ArrayList. I have written code for that but there is a logical error which I couldn't identify.

这是我的代码：

static void sortList(){

   List <Integer> number=new ArrayList <Integer>();

   number.add(11);
   number.add(45);
   number.add(12);
   number.add(32);
   number.add(36);

   System.out.println("Unsorted List: "+number);

   for (int i=0;i<number.size();i++){      
       int even=number.get(i)%2;       
        if (even==0){
            System.out.println("This is Even Number:"+ number.get(i));
            number.remove(i);
        }    
    }

    Collections.sort(number);
    System.out.println("Sorted List: "+number);

 }

代码的输出是：

Unsorted List: [11, 45, 12, 32, 36]
This is Even Number:12
This is Even Number:36
Sorted List: [11, 32, 45]

为什么32不捕获为偶数，因为它是一个偶数，我测试然后通过使用不同的偶数在相同的位置，但结果是相同的。为什么在索引（3）它的发生，任何偶数不能被捕获。我真的想知道为什么。

I am wondering that why 32 is not caught as an Even number as it is an even number, I tested then by using different even numbers at same position but the result is same. Why at index(3) its happening that any even number couldnt be catch. I am really wondering why. So please any one can help me out for this and is there any other better way to implement this solution.

感谢

推荐答案

使用 Iterator 。它有一个 remove（）方法，你需要。

List<Integer> numbers = new ArrayList<Integer>();

numbers.add(11);
numbers.add(45);
numbers.add(12);
numbers.add(32);
numbers.add(36);

System.out.println("Unsorted List: " + numbers);

for (Iterator<Integer> iterator = numbers.iterator(); iterator.hasNext();) {
    Integer number = iterator.next();
    if (number % 2 == 0) {
        System.out.println("This is Even Number: " + number);
        iterator.remove();
    }

}

Collections.sort(numbers);
System.out.println("Sorted List: " + numbers);

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