将非数字列表更改为数字列表? [英] Changing an non-numeric list to a numeric one?
问题描述
这些是先前定义的.
def get_service_code(service):
return str(service[0])
service_106_data = filter_routes(bus_stations, "106")
service_106 = make_service(service_106_data, "106")
#print(get_service_code(service_106)) --> should return 106
bus_stations这里是一个txt文件,其中包含这样的数字列表
bus_stations here is a txt file that contain a list of numbers like this
106,1,1,43009
106,1,2,43179
.
.
.
106,2,1,03239
106,2,2,03211
.
.
.
106,2,50,43171
106,2,51,43009
那么这也是先前定义的
def get_route(service, direction):
return str(service[int(direction)][0])
print(get_route(service_106, '1'))
应返回此
['43009', '43179', '43189', '43619', '43629', '42319', '28109', '28189', '28019', '20109', '17189', '17179', '17169', '17159', '19049', '19039', '19029', '19019', '11199', '11189', '11401', '11239', '11229', '11219', '11209', '13029', '13019', '09149', '09159', '09169', '09179', '09048', '09038', '08138', '08057', '08069', '04179', '02049', 'E0200', '02151', '02161', '02171', '03509', '03519', '03539', '03129', '03218', '03219']
现在假设方向'1'更改为非数字,例如'A4',我该如何编写代码以使' A4'变成'1' ??以下代码不适用于"A4",但适用于"1"
Suppose now the direction '1' is changed to a non-numeric number such as 'A4', how do I write my code such that 'A4' is turned into '1'?? The below code will not work for 'A4' but it works for '1'
def make_service(service_data, service_code):
routes = []
curr_route = []
first = service_data[0] #('106', 'A4', '1', '43009')
curr_dir = first[1] # 'A4' --> #how do I change this to '1' ?
#additional line no. 1
for entry in service_data:
direction = entry[1] #A4
stop = entry[3] #43009
if direction == curr_dir:
curr_route.append(stop) #[43009]
else:
routes.append(curr_route) #[[]]
curr_route = [stop] #[43009]
curr_dir = direction #A4
# addition no.2
routes.append(curr_route) #[43009]
#modification
return (service_code, routes) #("106", [43009])
service_106 = make_service(service_106_data, "106")
# for e.g make_service(('106', 'A4', '1', '43009') , "106"))
print(get_service_code((service_106)))
->预期收益为106
print(get_service_code((service_106)))
--> expected return is 106
推荐答案
您可以为元组service_data中的每个唯一元素或列表分配一个ID号. 通过将每个元素分配为字典dict_中的键.下面的函数,to_IDS将设置 字典dict_中ID号为id的service_data中的所有元素.
You can assign an ID number to each unique element in your tuple service_data, or a list by assigning each element as key in a dictionary, dict_. The function below, to_IDS will set all the elements in service_data with an IDnumber in the dictionary dict_.
service_data = ('106', 'A4', '1', '43009')
dict_ = {}
def to_IDS(service_data, dict_):
ids_from_service_data = [(dict_.setdefault(i, len(dict_)))for i in service_data]
return ids_from_service_data, dict_
print to_IDS(service_data, dict_)
Output: [0, 1, 2, 3], {'1': 2, '43009': 3, '106': 0, 'A4': 1})
Alternative solution;
service_data = ['106', 'A4', '1', '43009']
service_code = None
def make_service(service_data, service_code):
routes = []
curr_route = []
first = service_data[0] # will be 106, corresponding to index 0('106') in service_data
service_data[1] = 1 # 'A4' --># changes value on index 1 (A4) to value 1
curr_dir = service_data[1] # curr_dir is index 1(A4 in service_data
#additional line no. 1
direction = service_data[1] #direction is service_data1
stop = service_data[-1] # ends at last position in list, -1
if direction == curr_dir:
curr_route.append(stop) #[43009]
print curr_route
else:
routes.append(curr_route) #[[]]
curr_route = [stop] #[43009]
curr_dir = direction #A4
# addition no.2
routes.append(curr_route)
service_code = service_data[0]
return (service_code, routes) #("106", [43009])
print make_service(service_data, service_code)
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