如何在Swift中将十六进制转换为带符号的浮点数?使用正数可以正常工作，但不适用于负数 [英] How do you convert a hex to signed float in Swift? Works fine with positive number but doesn't work on negative

问题描述

let hexString = "0x42f9b6c9"
let toInt = Int32(truncatingBitPattern: strtoul(self, nil, 16))
let toFloat = Float(bitPattern: UInt32(self))

结果:1​​24.857

RESULT: 124.857

let hexString = "0xc2f9b6c9"
let toInt = Int32(truncatingBitPattern: strtoul(self, nil, 16))
let toFloat = Float(bitPattern: UInt32(self))

应用在此处崩溃，因为该值为负值，预期结果为-124.857

app crashes here because the value is negative, expected result is -124.857

请帮助.谢谢！

推荐答案

strtoul表示字符串为无符号长.尝试strtol

strtoul means string to unsigned long. Try strtol

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