printf在LLVM IR中不适用于浮点数 [英] printf doesn't work for floats in LLVM IR

问题描述

我想将浮点变量的值打印到屏幕上.我在LLVM IR代码中声明了printf()函数，它已成功链接.

I want to print the value of a floating point variable to the screen. I am declaring printf() function in the LLVM IR code, and it is linking in successfully.

每当我打印整数，字符数据类型或字符串时，printf()都会在C代码中将它们正常打印到屏幕上.但是，如果我将float传递给printf()，它会打印0.000000，而不是打印浮点数.我多次检查了源代码，似乎语法是正确的.它应该正在打印2.75！我正在看这段代码，我绝对不明白代码与我编写的代码有何不同之处.

Whenever I print an integer or a character data type, or a string, printf() prints them normally to the screen as it prints them in the C code. However, if I pass a float to printf(), instead of printing the floating point number, it prints 0.000000. I checked the source code multiple times and it seems that the syntax is correct. It should be printing 2.75! I am looking at this code and I absolutely do not understand how code has a different behavior than what I wrote it.

target datalayout = "e-m:e-i64:64-f80:128-n8:16:32:64-S128"
target triple = "x86_64-unknown-linux-gnu"

@obj1 = global {i32, float, i8} zeroinitializer

@format_string = constant [10 x i8] c"%i %f %c\0A\00"

declare i32 @printf(i8*, ...)

define i32 @main() {
entry:
    %obj1 = load {i32, float, i8}, {i32, float, i8}* @obj1

    %obj2 = insertvalue {i32, float, i8} %obj1, i32 44, 0
    %obj3 = insertvalue {i32, float, i8} %obj2, float 2.75, 1
    %obj4 = insertvalue {i32, float, i8} %obj3, i8 36, 2

    store {i32, float, i8} %obj4, {i32, float, i8}* @obj1

    %ptr.i32 = getelementptr {i32, float, i8}, {i32, float, i8}* @obj1, i32 0, i32 0
    %0 = load i32, i32* %ptr.i32
    %ptr.float = getelementptr {i32, float, i8}, {i32, float, i8}* @obj1, i32 0, i32 1
    %1 = load float, float* %ptr.float
    %ptr.i8 = getelementptr {i32, float, i8}, {i32, float, i8}* @obj1, i32 0, i32 2
    %2 = load i8, i8* %ptr.i8

    %format_ptr = getelementptr [10 x i8], [10 x i8]* @format_string, i64 0, i64 0
    call i32 (i8*, ...) @printf(i8* %format_ptr, i32 %0, float %1, i8 %2)

    ret i32 0
}

当我编译LLVM IR代码时，这是输出:

When I compile the LLVM IR code, this is the output:

$ llvm-as code.ll -o code.bc
$ lli code.bc
44 0.000000 $

它成功打印了整数和字符，但没有打印浮点数！

It successfully printed the integer and the character, but not the floating point number!

推荐答案

原因是printf是可变函数，可变函数将float参数提升为double.请参见为什么printf()将浮点数提高为两倍?

The reason is printf is a variadic function and variadic functions promote float arguments to double. See Why does printf() promote a float to a double?

因此，您应该先将%1转换为double，然后再将其传递给printf，这是clang所做的.例如

So you should first cast %1 to double before passing passing it to printf, which is what clang does. For example

void f() {
  float a = 1;
  printf("%f", a);
}

给予

@.str = private unnamed_addr constant [3 x i8] c"%f\00", align 1

define dso_local void @f() #0 !dbg !7 {
  %1 = alloca float, align 4
  call void @llvm.dbg.declare(metadata float* %1, metadata !11, 
                              metadata !DIExpression()), !dbg !13
  store float 1.000000e+00, float* %1, align 4, !dbg !13
  %2 = load float, float* %1, align 4, !dbg !14
  %3 = fpext float %2 to double, !dbg !14
  %4 = call i32 (i8*, ...) @printf(i8* getelementptr inbounds ([3 x 
            i8], [3 x i8]* @.str, i64 0, i64 0), double %3), !dbg !15
  ret void, !dbg !16
}

请注意fpext

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