将 isdigit 用于浮点数? [英] Using isdigit for floats?
本文介绍了将 isdigit 用于浮点数?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
a = raw_input('How much is 1 share in that company? ')
while not a.isdigit():
print("You need to write a number!
")
a = raw_input('How much is 1 share in that company? ')
这仅在用户输入 integer
时有效,但我希望即使他们输入 float
也能起作用,但在输入 string 时不起作用代码>.
This only works if the user enters an integer
, but I want it to work even if they enter a float
, but not when they enter a string
.
所以用户应该能够同时输入9
和9.2
,但不能输入abc
.
So the user should be able to enter both 9
and 9.2
, but not abc
.
我该怎么做?
推荐答案
使用正则表达式.
import re
p = re.compile('d+(.d+)?')
a = raw_input('How much is 1 share in that company? ')
while p.match(a) == None:
print "You need to write a number!
"
a = raw_input('How much is 1 share in that company? ')
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