JavaFX 3D:将圆柱体转换为定义的起点和终点 [英] JavaFX 3D: Transforming Cylinder to defined start and end points

问题描述

假设我希望Cylinder从某个3D点开始并在另一个3D点结束.

Suppose that I want a Cylinder to start in some 3D point and to end in some other 3D point.

据我所知，这样做的方法是计算两个点之间的欧几里得距离，并创建具有相同长度的圆柱体.然后，应平移并旋转圆柱体，使其真正在起点处开始，并在终点处结束.

As far as I know, the way to do that, is to compute the Euclidian distance between the 2 points and to create a Cylinder with the same length. Then, the cylinder should be translated and rotated, such that it really starts at the start point and ends at the end point.

我对这些转换感到迷惑，没有成功将圆柱体放置在正确的位置.

I get messed up with these transformation and do not succeed to place the Cylinder in its correct place.

能否请您分享该功能实现的一些代码段:

Could you please share some code snippet of implementation of the function:

void createCylinder(Group group, double p1X, double p1Y, double p1Z, 
                                 double p2X, double p2Y, double p2Z)

推荐答案

在找到解决方案时回答自己.

Answering myself as I've found a solution.

在此处找到了一个有效的代码段: http://netzwerg. ch/blog/2015/03/22/javafx-3d-line/

Found a working nice snippet here: http://netzwerg.ch/blog/2015/03/22/javafx-3d-line/

这是代码，很简单:

public Cylinder createConnection(Point3D origin, Point3D target) {
    Point3D yAxis = new Point3D(0, 1, 0);
    Point3D diff = target.subtract(origin);
    double height = diff.magnitude();

    Point3D mid = target.midpoint(origin);
    Translate moveToMidpoint = new Translate(mid.getX(), mid.getY(), mid.getZ());

    Point3D axisOfRotation = diff.crossProduct(yAxis);
    double angle = Math.acos(diff.normalize().dotProduct(yAxis));
    Rotate rotateAroundCenter = new Rotate(-Math.toDegrees(angle), axisOfRotation);

    Cylinder line = new Cylinder(1, height);

    line.getTransforms().addAll(moveToMidpoint, rotateAroundCenter);

    return line;
}

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