如何在Java中将数字转换为字母? [英] How do I convert a number to a letter in Java?

问题描述

是否有比这更好的将数字转换为字母等价的方式?

Is there a nicer way of converting a number to its alphabetic equivalent than this?

private String getCharForNumber(int i) {
    char[] alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ".toCharArray();
    if (i > 25) {
        return null;
    }
    return Character.toString(alphabet[i]);
}

也许可以优雅地处理大于26的数字呢?

Maybe something than can deal with numbers greater than 26 more elegantly too?

推荐答案

只需使用ASCII表示形式即可.

Just make use of the ASCII representation.

private String getCharForNumber(int i) {
    return i > 0 && i < 27 ? String.valueOf((char)(i + 64)) : null;
}

注意:这假定i在1和26之间(包括两端).

Note: This assumes that i is between 1 and 26 inclusive.

如果希望i从零开始，则必须将条件更改为i > -1 && i < 26，并将增量更改为65.

You'll have to change the condition to i > -1 && i < 26 and the increment to 65 if you want i to be zero-based.

这里是完整的ASCII表，以防您需要参考:

Here is the full ASCII table, in case you need to refer to:

正如一些人在这里建议的那样，直接使用字符'A'而不是其ASCII代码更具可读性.

As some folks suggested here, it's much more readable to directly use the character 'A' instead of its ASCII code.

private String getCharForNumber(int i) {
    return i > 0 && i < 27 ? String.valueOf((char)(i + 'A' - 1)) : null;
}

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