在整个数据框中将字母转换为数字 [英] Converting letters to numbers in entire dataframe

问题描述

我无法在数据框的所有列上应用 chartr（）函数来将字母转换为数字。

I am having trouble applying the chartr() function on all columns of my data frame for converting letters to numbers.

我设法在单列上执行此操作，但是我希望能够在整个数据帧上执行此操作。这是我的数据示例：

I managed doing it on single columns, yet I want to be able to do it on the entire data frame. Here is an example of my data:

ID = c(1,2,3)
POS1 = c('AG','GC','TT')
POS2 = c('GT','CC','TC')
POS3 = c('GG','CT','AT')
DF = data.frame(ID,POS1,POS2,POS3)

DF$POS1X <- chartr('ACGT','1234',DF$POS1)

  ID POS1 POS2 POS3 POS1X
1  1   AG   GT   GG    13
2  2   GC   CC   CT    32
3  3   TT   TC   AT    44

从代码中可以看到，我想将A转换为1，将C转换为2，G转换为3，将T转换为4。我有40 +列并因此重复执行超过40次以上的相同命令将是不切实际的（特别是如果以后在遇到类似问题时说几百列）

As seen from the code, I want to convert A to 1, C to 2, G to 3, and T to 4. I have 40+ columns and thus repeating the same command as above 40+ times would be impractical (especially if I run into the same problem later on with say hundreds of columns)

ykl

Sincerily, ykl

推荐答案

为什么不使用 lapply ？

DF2 <- DF ## to not overwrite the original DF
DF2[-1] <- lapply(DF2[-1], chartr, old = "ACGT", new = "1234")
DF2
#   ID POS1 POS2 POS3
# 1  1   13   34   33
# 2  2   32   22   24
# 3  3   44   42   14

现在您有两个具有相同列名的数据框，与将新列附加到旧数据相比，我发现比较起来比较容易。尤其是当列很多时。

Now you have two data frames with equivalent column names which I find easier to compare than appending new columns to the old data. Especially when there are many many columns.

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