R将整个数据帧中的字母转换为数字 [英] R Converting letters to numbers in entire dataframe

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问题描述

我无法在数据框的所有列上应用 chartr()函数,以将字母转换为数字。


$ b $我管理在单列上进行管理,但我希望能够在整个数据框架上执行此操作。以下是我的数据示例:

  ID = c(1,2,3)
POS1 = c 'AG','GC','TT')
POS2 = c('GT','CC','TC')
POS3 = c('GG','CT' ')
DF = data.frame(ID,POS1,POS2,POS3)

DF $ POS1X< - chartr('ACGT','1234',DF $ POS1)

ID POS1 POS2 POS3 POS1X
1 1 AG GT GG 13
2 2 GC CC CT 32
3 3 TT TC AT 44

从代码中可以看出,我要将A转换为1,将C转换为2,将G转换为3,将T转换为4.我有40 +列,因此重复与上述相同的命令40+次将是不切实际的(特别是如果我遇到相同的问题后来说几百列)




ykl

解决方案

为什么不使用 lapply



  DF2 < -  DF ##以不覆盖原始DF 
DF2 [-1]< - lapply(DF2 [-1],chartr,old =ACGT,new =1234)
DF2
#ID POS1 POS2 POS3
#1 1 13 34 33
#2 2 32 22 24
#3 3 44 42 14
/ pre>

现在,您有两个具有等效列名称的数据帧,我发现比将旧列添加到旧数据更容易进行比较。特别是当有很多列时。


I am having trouble applying the chartr() function on all columns of my data frame for converting letters to numbers.

I managed doing it on single columns, yet I want to be able to do it on the entire data frame. Here is an example of my data:

ID = c(1,2,3)
POS1 = c('AG','GC','TT')
POS2 = c('GT','CC','TC')
POS3 = c('GG','CT','AT')
DF = data.frame(ID,POS1,POS2,POS3)

DF$POS1X <- chartr('ACGT','1234',DF$POS1)

  ID POS1 POS2 POS3 POS1X
1  1   AG   GT   GG    13
2  2   GC   CC   CT    32
3  3   TT   TC   AT    44

As seen from the code, I want to convert A to 1, C to 2, G to 3, and T to 4. I have 40+ columns and thus repeating the same command as above 40+ times would be impractical (especially if I run into the same problem later on with say hundreds of columns)

Sincerily, ykl

解决方案

Why not use lapply?

DF2 <- DF ## to not overwrite the original DF
DF2[-1] <- lapply(DF2[-1], chartr, old = "ACGT", new = "1234")
DF2
#   ID POS1 POS2 POS3
# 1  1   13   34   33
# 2  2   32   22   24
# 3  3   44   42   14

Now you have two data frames with equivalent column names which I find easier to compare than appending new columns to the old data. Especially when there are many many columns.

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