Java中的概率 [英] Probability in Java

问题描述

我很好奇，我该如何在Java中实现概率?例如，如果变量显示的机会是1/25，那么我将如何实现呢?还是其他可能性?请指出我的大致方向.

I was curious to know, how do I implement probability in Java? For example, if the chances of a variable showing is 1/25, then how would I implement that? Or any other probability? Please point me in the general direction.

推荐答案

您将使用

You'd use Random to generate a random number, then test it against a literal to match the probability you're trying to achieve.

所以给定了:

boolean val = new Random().nextInt(25)==0;

val的概率为1/25(因为nextInt()的概率为返回从0到25(但不包括25)的任何数字).

val will have a 1/25 probability of being true (since nextInt() has an even probability of returning any number starting at 0 and up to, but not including, 25.)

您当然也必须import java.util.Random;.

如下所述，如果您获得多个随机数，则重用Random对象而不是始终重新创建它会更有效:

As pointed out below, if you're getting more than one random number it'd be more efficient to reuse the Random object rather than recreating it all the time:

Random rand = new Random();
boolean val = rand.nextInt(25)==0;

..

boolean val2 = rand.nextInt(25)==0;

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