如何使用php将hijri日期转换为公历日期? [英] how to convert hijri date to gregorian date using php?

问题描述

请帮助我

如何使用php将回历日期转换为公历日期

how to convert hijri date to Gregorian date using php

如果您知道任何可以将hijri转换为Gregorian的日期选择器，请告诉我.

if you know any date picker which can convert hijri to Gregorian, please let me know.

推荐答案

选中此解决方案.在这里引用

<?php

class HijriCalendar
{
    function monthName($i) // $i = 1..12
    {
        static $month  = array(
            "Muḥarram", "Safar", "Rabī‘ I", "Rabī‘ II",
            "Jumādá I", "Jumādá II", "Rajab", "Sha‘bān",
            "Ramaḍān", "Shawwāl", "Dhū al-Qa‘dah", "Dhū al-Ḥijjah"
        );
        return $month[$i-1];
    }

    function GregorianToHijri($time = null)
    {
        if ($time === null) $time = time();
        $m = date('m', $time);
        $d = date('d', $time);
        $y = date('Y', $time);

        return HijriCalendar::JDToHijri(
            cal_to_jd(CAL_GREGORIAN, $m, $d, $y));
    }

    function HijriToGregorian($m, $d, $y)
    {
        return jd_to_cal(CAL_GREGORIAN,
            HijriCalendar::HijriToJD($m, $d, $y));
    }

    # Julian Day Count To Hijri
    function JDToHijri($jd)
    {
        $jd = $jd - 1948440 + 10632;
        $n  = (int)(($jd - 1) / 10631);
        $jd = $jd - 10631 * $n + 354;
        $j  = ((int)((10985 - $jd) / 5316)) *
            ((int)(50 * $jd / 17719)) +
            ((int)($jd / 5670)) *
            ((int)(43 * $jd / 15238));
        $jd = $jd - ((int)((30 - $j) / 15)) *
            ((int)((17719 * $j) / 50)) -
            ((int)($j / 16)) *
            ((int)((15238 * $j) / 43)) + 29;
        $m  = (int)(24 * $jd / 709);
        $d  = $jd - (int)(709 * $m / 24);
        $y  = 30*$n + $j - 30;

        return array($m, $d, $y);
    }

    # Hijri To Julian Day Count
    function HijriToJD($m, $d, $y)
    {
        return (int)((11 * $y + 3) / 30) +
            354 * $y + 30 * $m -
            (int)(($m - 1) / 2) + $d + 1948440 - 385;
    }
};

$hijri = HijriCalendar::GregorianToHijri( time() );
echo $hijri[1].'. '.HijriCalendar::monthName($hijri[0]).' '.$hijri[2];

?>

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