C ++如何正确证明多条数据的合理性 [英] C++ how to right justify multiple pieces of data

问题描述

所以我必须向std::cout发送一列数据，在其中我还必须在数据周围显示一些字符，例如:

So I have to send to std::cout a column of data where I have to also display some characters around the data like:

    Plot Points
   (0,0), (2,3) 
(1,10), (12,14)

在这里我必须右对齐列标题中"Points"中字母"s"下的最后一个右括号.

where I have to right justify the last right parenthesis under the letter "s" in "Points" in the column header.

我正在像这样发布数据

cout << right << setw(12) << "(" << x1 << "," << y1 << "), (" << x2 << "," << y2 << ")";

但是我看到的所有示例似乎都表明正确的setw似乎只影响我发送给cout的下一条数据，因此在这种情况下仅影响"(".

But all the examples I have seen seem to show that the right and setw only seem to affect the next piece of data I send to cout, so in this case the "(" only.

有没有办法将所有这些字符和变量组合在一起，以使它们在输出列中全部对齐?

Is there any way to group all those characters and variables together to have them all justified together in the column of output?

我只是在学习C ++，所以希望有一些我还没有学到的简单解决方案吗?

I'm just learning C++ so expect there is some simple solution I haven't learned yet?

推荐答案

有没有办法将所有这些字符和变量组合在一起，以使它们在输出列中全部对齐?

Is there any way to group all those characters and variables together to have them all justified together in the column of output?

是的，您可以使用一些辅助函数来构建字符串:

Yes, you can use a little helper function to build a string:

std::string parentized_pair(int x, int y) {
    std::ostringstream oss;
    oss << "(" << x "," << y << ")";
    return oss.str();
}

并在最终输出中使用那个:

and use that one in the final output:

cout << right << setw(12) << parentized_pair(x1,y1) 
     << right << setw(12) << parentized_pair(x2,y2);

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