创建一个从字符串中获取字符切片的滑动窗口迭代器 [英] Creating a sliding window iterator of slices of chars from a String

问题描述

我正在寻找使用我了解如何以这种方式使用Windows:

I understand how to use windows this way:

fn main() {
    let tst = ['a', 'b', 'c', 'd', 'e', 'f', 'g'];
    let mut windows = tst.windows(3);

    // prints ['a', 'b', 'c']
    println!("{:?}", windows.next().unwrap());
    // prints ['b', 'c', 'd']
    println!("{:?}", windows.next().unwrap());
    // etc...
}

但是解决这个问题时我有点迷路:

But I am a bit lost when working this problem:

fn main() {
    let tst = String::from("abcdefg");
    let inter = ? //somehow create slice of character from tst
    let mut windows = inter.windows(3);

    // prints ['a', 'b', 'c']
    println!("{:?}", windows.next().unwrap());
    // prints ['b', 'c', 'd']
    println!("{:?}", windows.next().unwrap());
    // etc...
}

本质上，我正在寻找如何将字符串转换为可以与window方法一起使用的char切片.

Essentially, I am looking for how to convert a string into a char slice that I can use the window method with.

推荐答案

此解决方案将为您效用. (游乐场)

This solution will work for your purpose. (playground)

fn main() {
    let tst = String::from("abcdefg");
    let inter = tst.chars().collect::<Vec<char>>();
    let mut windows = inter.windows(3);

    // prints ['a', 'b', 'c']
    println!("{:?}", windows.next().unwrap());
    // prints ['b', 'c', 'd']
    println!("{:?}", windows.next().unwrap());
    // etc...
    println!("{:?}", windows.next().unwrap());
}

字符串可以遍历其字符，但这不是一个切片，因此您必须将其收集到一个vec中，然后将其强制转换为一个切片.

String can iterate over its chars, but it's not a slice, so you have to collect it into a vec, which then coerces into a slice.

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