WebM流的媒体源扩展appendBuffer以随机顺序 [英] Media Source Extensions appendBuffer of WebM stream in random order
问题描述
我正在尝试从多个来源并行实现视频下载.但是,如果不遵循视频文件的顺序,MSE appendBuffer方法总是失败.
I am trying to achieve video downloading in parallel from multiple sources. However MSE appendBuffer method always fails when not following sequence order of video file.
我想按随机顺序附加各个部分,并尽快"播放视频. 我正在探索SourceBuffer模式属性以及timestampOffset.这些都没有帮助.
I would like to append parts in random order and play video "as soon as possible". I was exploring SourceBuffer mode property as well as timestampOffset. None of those were helpful.
我想知道我拥有的源webm文件是否可以以不支持的格式"来执行此任务(顺序方法可以正常工作).
I am wondering if source webm file i have could be in "not supported format" for such a task (sequential approach works fine).
谢谢您的任何建议.
更新: 我尝试分析众所周知的示例视频文件,我发现有可能将其部分乱序地添加.似乎有必要遵循集群字节范围:
UPDATE: I tried to analyse well known example video file and i figured out that it is possible to append parts of it out of order. Seems like it is necessary to follow Cluster byte ranges:
<Cluster type="list" offset="4357">
<Timecode type="uint" value="0"/>
<SimpleBlock type="binary" size="7723" trackNum="1" timecode="0" presentationTimecode="0" flags="80"/>
<SimpleBlock type="binary" size="5" trackNum="2" timecode="0" presentationTimecode="0" flags="80"/>
...
</Cluster>
<Cluster type="list" offset="16187">
<Timecode type="uint" value="385"/>
<SimpleBlock type="binary" size="5" trackNum="2" timecode="0" presentationTimecode="385" flags="80"/>
<SimpleBlock type="binary" size="4968" trackNum="1" timecode="13" presentationTimecode="398" flags="80"/>
...
</Cluster>
推荐答案
在研究了webm格式规范之后,编译了libwebm工具并研究了DASH,我最终弄清楚了如何使MSE appendBuffer以任何顺序工作!
After digging into webm format specification, compiling libwebm tools and studying DASH i finally figured out how to make MSE appendBuffer working in any order!
- ffmpeg -i result.webm -g 10 -c:v libvpx resultClusters.webm(也可以使用libvpx-vp9)
- mkvmuxer_sample -i resultClusters.webm -o resultRepaired.webm
- mse_json_manifest resultRepaired.webm >> manifest.json
您将在stdout上获得类似的内容:
You will get on stdout something like:
{
"type": "video/webm; codecs=\"vp8\"",
"duration": 27771.000000,
"init": { "offset": 0, "size": 258},
"media": [
{ "offset": 258, "size": 54761, "timecode": 0.000000 },
{ "offset": 55019, "size": 166431, "timecode": 2.048000 },
{ "offset": 221450, "size": 49258, "timecode": 4.130000 },
{ "offset": 270708, "size": 29677, "timecode": 6.148000 },
{ "offset": 300385, "size": 219929, "timecode": 8.232000 },
{ "offset": 520314, "size": 25132, "timecode": 10.335000 },
{ "offset": 545446, "size": 180777, "timecode": 12.440000 },
{ "offset": 726223, "size": 76107, "timecode": 14.471000 },
{ "offset": 802330, "size": 376557, "timecode": 14.794000 },
{ "offset": 1178887, "size": 247138, "timecode": 16.877000 },
{ "offset": 1426025, "size": 78468, "timecode": 18.915000 },
{ "offset": 1504493, "size": 25614, "timecode": 20.991000 },
{ "offset": 1530107, "size": 368277, "timecode": 23.093000 },
{ "offset": 1898384, "size": 382847, "timecode": 25.097000 },
{ "offset": 2281231, "size": 10808, "timecode": 27.135000 }
]
}
现在您要做的就是首先加载元数据xhr.setRequestHeader("Range", "bytes=0-257");
,然后在 ANY ORDER 中所有其他段.例如.第二段范围是55019-221449
个字节.
Now all you have to do is firstly load metadata xhr.setRequestHeader("Range", "bytes=0-257");
and then in ANY ORDER all other segments. E.g. second segment range is 55019-221449
bytes.
说明:
最重要的是 ffmpeg 重新编码,并将帧组设置为您想要的群集大小.在此示例中,我选择了非常低的阈值(每10帧),但是您可以选择更高的导致生成的簇更少(媒体"数组中的项目更少).
The most important thing is ffmpeg reencoding with group of frames set to the size of cluster you would like to have. In this example i choose pretty low threshold (each 10 frames) but you can choose higher causing fewer clusters are generated (less items in "media" array).
此后,您必须以经典方式(使用 libwebm 中的 sample_muxer )修复提示,然后就可以开始使用了.
After that you have to fix cues in the classic way (using sample_muxer from libwebm) and you are ready to go.
经过以下测试:Chrome 51,Firefox 47.
Tested on: Chrome 51, Firefox 47.
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