存取器变异器方法(Python) [英] Accessor & Mutator methods (Python)
问题描述
我正在尝试找出Python中的封装.我在shell中进行了一个简单的小测试,以了解某些东西是如何工作的以及它是否像我期望的那样工作.而且我无法使其正常工作.这是我的代码:
I am trying to figure out encapsulation in Python. I was doing a simple little test in shell to see how something worked and it doesn't work like I was expecting. And I can't get it to work. Here's my code:
class Car:
def __init__(self, carMake, yrMod):
self.__make = carMake
self.__yearModel = yrMod
self.__speed = 0
#Mutator Methods
def set_make(self, make):
self.__make = carMake
def set_model(self, yrMod):
self.__yearModel = yrMod
#def set_speed(self, speed):
#self.__speed = speed
#Accessor Methods
def get_make(self):
return self.__make
def get_yearModel(self):
return self.__yearModel
def get_speed(self):
return self.__speed
myCar=Car('Ford', 1968)
myCar2=Car('Nissan', 2012)
myCar.get_make()
'Ford'
myCar.set_make=('Porche')
myCar.get_make()
'Ford'
myCar.set_make为什么不将福特更改为保时捷?谢谢.
Why doesn't myCar.set_make change Ford into Porche? Thank you.
推荐答案
使用myCar.set_make=('Porche')
,您将此成员的Car类设置为'Porche'
字符串,但未调用该方法.
With myCar.set_make=('Porche')
, you are setting this member the Car class as the 'Porche'
string, but you are not calling the method.
只需删除=
即可解决该问题:
Just remove the =
to solve it:
myCar.set_make('Porche')
myCar.get_make() # Porche
此外,正如@DSM所指出的,set_make
的参数中存在错误:
Besides, as @DSM points out, there is an error in the argument of set_make
:
def set_make(self, make):
self.__make = make # carMake is not defined!
但是,此用法强烈建议不要使用Python中的getter和setter方法.如果出于任何原因需要类似的东西,请考虑使用属性.
However, this use of getters and setters in Python is strongly discouraged. If you need something similar for any reason, consider using properties.
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