按数字顺序对目录中的文件进行排序和列出 [英] Sort and list the files from a directory in numeric order

问题描述

这是我的文件夹结构.

/home/files/encounters 9-22-11-0.jpg ../home/files/encounters 9-22-11- [n] .jpg

/home/files/encounters 9-22-11-0.jpg .. /home/files/encounters 9-22-11-[n].jpg

puts Dir.glob("/home/files/*.jpg")[0] 

当我执行上述代码时，它显示了第六个文件(索引5 =>/home/files/encounters 9-22-11-5.jpg)，但实际上我需要将输出作为第一个文件(索引0 = >/home/files/encounters 9-22-11-0.jpg)

When i execute the above code, it displayed the sixth file (index 5 => /home/files/encounters 9-22-11-5.jpg), but actually i need the output as first file(index 0 => /home/files/encounters 9-22-11-0.jpg)

如何按照用户定义的排序顺序对文件进行排序?喜欢

How can i sort the files as user defined sorting order?. like

当我尝试..
.. [0] =>/home/files/encounters 9-22-11-5.jpg
.. [1] =>/home/files/encounters 9-22-11-21.jpg
.. [2] =>/home/files/encounters 9-22-11-39.jpg

When i tried..
..[0] => /home/files/encounters 9-22-11-5.jpg
..[1] => /home/files/encounters 9-22-11-21.jpg
..[2] => /home/files/encounters 9-22-11-39.jpg

但是，我需要
.. [0] =>/home/files/encounters 9-22-11-0.jpg
.. [1] =>/home/files/encounters 9-22-11-1.jpg
.. [2] =>/home/files/encounters 9-22-11-2.jpg

But, I need
..[0] => /home/files/encounters 9-22-11-0.jpg
..[1] => /home/files/encounters 9-22-11-1.jpg
..[2] => /home/files/encounters 9-22-11-2.jpg

其他信息，排序也不起作用.

Additional information, sorting is also not working.

f = Dir.glob("/home/files/*.jpg").sort
f [0] =>/home/files/encounters 9-22-11-0.jpg
f [0] =>/home/files/encounters 9-22-11-1.jpg
f [0] =>/home/files/encounters 9-22-11-10.jpg
f [0] =>/home/files/encounters 9-22-11-11.jpg

f = Dir.glob("/home/files/*.jpg").sort
f[0] => /home/files/encounters 9-22-11-0.jpg
f[0] => /home/files/encounters 9-22-11-1.jpg
f[0] => /home/files/encounters 9-22-11-10.jpg
f[0] => /home/files/encounters 9-22-11-11.jpg

推荐答案

puts Dir.glob("/home/files/*.jpg").sort

如果您使用的格式是11-09-22-05.jpg而不是9-22-11-5.jpg，则可以工作.您可以尝试将它们排序为数字.

Would work if you had a format like 11-09-22-05.jpg instead of 9-22-11-5.jpg. You could try to sort them as a number instead.

Dir.glob("/home/files/*.jpg").sort_by {|s| s.gsub("-","").to_i }

但是似乎您有month-day-year-number，所以我想正确的排序方式要复杂得多.

But as it seems you have month-day-year-number I guess that the correct way to sort is a bit more complicated than that.

arr=%w[9-22-12-33.jpg 9-22-11-5.jpg 9-22-10-99.jpg 12-24-11-1.jpg]
arr.sort_by do |s|
  t = s.split("-").map(&:to_i)
  [t[2], t[0], t[1], t[3]]
end

它的工作方式是将9-22-11-5.jpg重新格式化为包含[11, 9, 22, 5]的数组，然后对其进行排序.

It works by reformatting 9-22-11-5.jpg to an array containing [11, 9, 22, 5] and then sorts by that instead.

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