Python:如何按数字顺序对 .txt 文件的内容进行排序? [英] Python: How do you sort the contents of a .txt file in numerical order?

问题描述

我在编写按数字顺序排列 .txt 文件的代码时遇到了一些麻烦.

I have some trouble making a code that arranges a .txt file in numerical order.

我遇到的问题是，在 .txt 文件中订购数字 77、45、85、100 时，它会将其订购为 100、45、77、85；100 是最低的.

The problem I'm having is when ordering numbers 77, 45, 85, 100 in the .txt file it orders it as 100, 45, 77, 85; 100 being the lowest.

不确定我会如何更正，因为我希望 100 是最高的.

Not sure how I would correct that as I want 100 to be the highest.

这是我目前所拥有的:

import csv
import operator


sample = open("score.txt")
csv1 = csv.reader(sample, delimiter=',')
sort = sorted(csv1, key=operator.itemgetter(1))
for eachline in sort:
    print eachline

推荐答案

就像budder 所说的那样，尝试将您的元素转换为int 或float.假设您正在使用整数，您可以在 sorted() func:

Like budder says, try to convert your elements to int or float. Assuming that your are working with integers you can change your key in sorted() func:

sort = sorted(csv1, key=lambda x : int(x[1]))

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