正则表达式删除非14位数字的任何内容，后跟空格 [英] Regex removing anything that is not a 14-digit number followed with space

问题描述

我正试图反转此表达式:([0-9]{14} )， 因此所有14位数字后跟一个空格.

I'm trying to invert this expression: ([0-9]{14} ), so all 14 digit numbers followed by a space.

我到处看，似乎最好的方法应该是使用负向超前.
但是，当我尝试将q(?!u)应用于我的案例>> (?!([0-9]{14} ))时，它不起作用.

I looked everywhere, and it seems that the best way should be using negative lookahead.
But when I try apply q(?!u) to my case >> (?!([0-9]{14} )), it doesn't work.

我在做什么错了?

我将为您提供任何建议，谢谢.

I will appreaciate any advice, thank you.

关键是要删除所有14位文本块以外的内容，同时保留这些14位文本块.

The point is to remove everything that is not a 14-digit chunk of text while preserving those 14-digit chunks.

推荐答案

如果要删除除14位数字之外的带空格的文本，请使用(\b\d{14} )|.并替换为$1.

If you want to delete text other than 14 digits followed with a space, use (\b\d{14} )|. and replace with $1.

模式匹配并捕获 (我们可以参考使用

The pattern matches and captures (we can refer to the text captured with a backreference in the replacement pattern) the 14-digit chunks and then a space as whole word due to \b (a word boundary). If this text is not found, any character other than a newline is matched with . and is not captured (we cannot refer to it with a backreference).

因此，当我们用向后引用$1替换时，我们只是将匹配的14位数据块恢复为空格.

Thus, when we replace with a backreference $1, we just restore the matched 14 digit chunk with a space.

请参见regex101.com上的 regex演示.

See the regex demo at regex101.com.

要获得更清晰的视图，请删除所有空行:Edit> Line Operations> Remove Empty Lines.

To get the cleaner view, remove all empty lines: Edit > Line Operations > Remove Empty Lines.

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