使用正则表达式进行局部匹配，负向提前 [英] Partial match with negative lookahead using regex

问题描述

使用正则表达式负向查找，我必须搜索一个文本文件并标识一个部分已知的文本行，然后再不跟随另一部分已知的文本行.这是文本文件的简化示例:

Using regex with negative lookahead I have to search a text file and identify a partially known line of text that is NOT followed by another partially known line of text. This is a simplified example of the text file:

blahblahblah.Name=qwqwqwqwqw
abracadabra.Surname=ererererer
zxzxzxzxzx.Name=kmkmkmkmkmkm
oioioioi.Name=dfdfdfdfdfdf
popopopopopopo.Surname=lklklklklklklk

在上面的示例中，您可以看到以下模式:带有 Name 的行应始终跟有带有 Surname 的行，但有时不会发生.我必须确定那些名称行"后面没有姓氏行".

In the sample above you can see the pattern where a line with Name should always follow by a line with Surname, but sometimes it doesn't happen. I have to identify those "Name lines" which are not followed by the "Surname lines".

我正在Eclipse中使用文件搜索(它支持正则表达式).

I am using File Search in Eclipse (it supports regex).

我猜这是我最好的尝试之一，但是仍然不能解决问题:

This is one of my best attempts, I guess, but it still doesn't do the trick:

(名称.* \ n)(?！.*姓氏)

(Name.*\n)(?!.*Surname)

请分享您的想法. 亲切的问候.

Please share your thoughts. Kind regards.

推荐答案

.*\bName=.*\n(?!.*\bSurname=)可以.

以下是Python中的示例.

Below is an example in Python.

import re
s='''blahblahblah.Name=qwqwqwqwqw
abracadabra.Surname=ererererer
zxzxzxzxzx.Name=kmkmkmkmkmkm
oioioioi.Name=dfdfdfdfdfdf
popopopopopopo.Surname=lklklklklklklk'''
print(re.findall(r'\bName=.*\n(?!.*\bSurname=)', s))

这将输出:

['zxzxzxzxzx.Name=kmkmkmkmkmkm\n']

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