将代码转换为Swift 4.2时，通知名称错误 [英] Error with notification names while converting code to Swift 4.2

问题描述

下面的代码在Swift 4.2之前运行良好:

The code below was working fine before Swift 4.2:

NotificationCenter.default.addObserver(self, selector: #selector(keyboardWillChange(notification:)), name: NSNotification.Name.UIKeyboardWillShow, object: nil)

当我单击修复"选项时，它变为:

When I click the 'Fix' option, it becomes:

NotificationCenter.default.addObserver(self, selector: #selector(keyboardWillChange(notification:)), name: NSNotification.Name.UIResponder.keyboardWillShowNotification, object: nil)

但是它仍然被标记为错误.这是解释:

But it is still marked an error. Here is the explanation:

Type 'NSNotification.Name' has no member 'UIResponder'

然后我尝试删除'UIResponder':

And then I tried to delete 'UIResponder':

NotificationCenter.default.addObserver(self, selector: #selector(keyboardWillChange(notification:)), name: NSNotification.Name.

...但是我不知道该如何完成.

...but I don't know how should I complete it.

推荐答案

正确的格式是:

UIResponder.keyboardWillShowNotification

...因此，您的代码变为:

...so, your code becomes:

NotificationCenter.default.addObserver(
    self, 
    selector: #selector(keyboardWillChange(notification:)), 
    name: UIResponder.keyboardWillShowNotification, 
    object: nil
)

这是Xcode 10的一个已知问题.在更正通知名称时，自动修复功能无法在Swift 4.2上正常工作.

This is a known issue with Xcode 10. Automatic Fix-it is not working correctly for Swift 4.2 when it comes to correcting notification names.

在Swift 4.2中，许多Notification.Name实例成为其他类中的实例变量.例如，keyboardWillShowNotification现在是UIResponder的实例变量.

In Swift 4.2, lots of Notification.Name instances became instance variables in other classes. For example, keyboardWillShowNotification is now an instance variable of UIResponder.

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