Opendir函数为我提供了多个数组，而不仅仅是一个 [英] Opendir function gives me multiple arrays instead of just one

问题描述

敬礼，代码长老，

我正在寻求掌握PHP的法术，现在需要您的协助来杀死一头强大的野兽.

I am on a quest to master the spells of PHP, and now need your assistance in slaying a mighty beast.

我正在用PHP制作REST API.函数之一是GET，该GET返回目录中的png列表.但是，它不返回一个数组，而是返回多个数组(每次迭代一个数组?).

I'm making a REST API in PHP. One of the functions is a GET that returns a list of pngs in a dir. But instead of returning one array, it returns multiple arrays (one for each iteration?).

我想要:

["1.png","2.png","3.png"]

但是我得到了:

["1.png"]["1.png","2.png"]["1.png","2.png","3.png"]

我表现出可鄙的侮辱和屈辱功能:

I present my pitiful function for scorn and humiliation:

function getPics() {
$pic_array = Array(); 
$handle =    opendir('/srv/dir/pics'); 
while (false !== ($file = readdir($handle))) { 
    if ($file!= "." && $file!= ".." &&!is_dir($file)) { 
    $namearr = explode('.',$file); 
    if ($namearr[count($namearr)-1] == 'png') $pic_array[] = $file; 
    } 
echo json_encode($pic_array);
} 
closedir($handle);
}

推荐答案

您应该进行适当的缩进，这很清楚出了什么问题.您将echo json_encode() 放入循环中.这是更正的版本:

You should do some proper indenting and it will be very clear what was wrong. You put the echo json_encode() in the loop. This is a corrected version:

function getPics()
{
    $pic_array = Array(); 
    $handle = opendir('/srv/dir/pics'); 
    while ( false !== ($file = readdir($handle)) )
    {
        if ( $file=="." || $file==".." || is_dir($file) ) continue; 
        $namearr = explode('.',$file);
        if ($namearr[count($namearr)-1] == 'png') $pic_array[] = $file; 
    } 
    echo json_encode($pic_array);
    closedir($handle);
}

请注意，这种检查扩展名失败的方式存在一个小缺陷，即匹配名为"png"(无扩展名)的文件.有几种方法可以解决此问题，例如通过使用pathinfo()分析文件名.

Note that this way of checking the extension fails has a minor flaw, in that a file named "png" (with no extension) will match. There are several ways to fix this, e.g. by using pathinfo() to analyse the filename.

ps.也不是这样:

if ( $file=="." || $file==".." || is_dir($file) ) continue; 

可以写为

if ( is_dir($file) ) continue; 

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