bash的浮点运算 [英] floating-point operations with bash

问题描述

如何在bash脚本中将字符串"620/100"转换为"6.2"

how can I transform the string "620/100" into "6.2" in a bash script

我的问题的背景与图像处理有关. EXIF数据以小数格式编码焦距，而我需要相应的十进制字符串.

The context of my question is about image processing. EXIF data are coding the focal length in fractional format, while I need the corresponding decimal string.

感谢您的帮助，奥利维尔

Thanks for helping, Olivier

推荐答案

使用bc -l

bc -l <<< "scale=2; 620/100"
6.20

或awk:

awk 'BEGIN{printf "%.2f\n", (620/100)}'
6.20

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