bash中的浮点除法 [英] Floating-point division in bash

问题描述

我正在尝试将用户输入的任何数字转换为2个小数位. 例如

What is the total cost in cents? 2345
output: 23.45

这是我到目前为止的代码

percentage=20 #cannot change numerical value must convert into 0.20
echo -n "What is the total cost? ";
read cost_in_cents
echo "scale 1; $cost_in_cents" | bc

我还要对百分比进行乘法运算，如何将百分比转换为浮点数(0.20)

解决方案

也许是对逆波兰表示法计算器的怀旧之情，但我在这里使用dc而不是bc:

dc <<<"2 k $cost_in_cents 100 / p"

正确地，输出是浮点数(精度的小数点后两位).

完全相同的代码，无需进行任何更改，即可将20转换为.20.

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有关bash中浮点数学的完整讨论，请参见 BashFAQ#22 . /p>

I'm trying to convert whatever numbers the user inputs into 2 decimal places. For instance

What is the total cost in cents? 2345
output: 23.45

this is the code i have so far

percentage=20 #cannot change numerical value must convert into 0.20
echo -n "What is the total cost? ";
read cost_in_cents
echo "scale 1; $cost_in_cents" | bc

I'm also going to be doing some multiplication with percentage, how can i also convert the percentage into a float (0.20)

解决方案

Perhaps it's nostalgia for reverse polish notation desk calculators, but I'd use dc rather than bc here:

dc <<<"2 k $cost_in_cents 100 / p"

Output is, properly, a float (with two digits past the decimal point of precision).

The exact same code, with no changes whatsoever, will work to convert 20 to .20.

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See BashFAQ #22 for a full discussion on floating-point math in bash.

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