如何实现在没有除法的硬件二进制浮点除法和无浮点硬件 [英] How to implement floating point division in binary with no division hardware and no floating point hardware

问题描述

我想知道如何实现IEEE-754 32位单precision浮点除法在没有除法的硬件二进制和没有浮点硬件？

I am wondering how to implement IEEE-754 32-bit single precision floating point division in binary with no division hardware and no floating point hardware?

我已经转向硬件，加，减，乘。

I have shifting hardware, add, subtract, and multiply.

我已经执行浮点乘法，加法，并使用16位字减法。

I have already implemented floating point multiplication, addition, and subtraction using 16-bit words.

我在一个专用的多核处理器执行这些指令和汇编写我的code。在此之前，我使用MATLAB来验证我的算法。

I am implementing these instructions on a proprietary multicore processor and writing my code in assembly. Beforehand, I am using matlab to verify my algorithm.

我知道我需要减去的指数，但我怎么对尾数执行无符号除法？

I know I need to subtract the exponents, but how do i perform unsigned division on the mantissas?

推荐答案

取决于你想多么复杂，使之。保持它相当简单的，你可以通过倒数近似值尝试分工。

Depends on how complicated you want to make it. Keeping it reasonably simple, you could try division by reciprocal approximation.

而不是计算：（N / D）你锻炼：N *（1 / D）

Rather than calculating: (n / d) you'd work out: n * (1 / d).

要做到这一点你需要使用一些方法来制定的倒数，例如，的牛顿迭代它使用牛顿的方法来计算除数，直到它的倒数先后更加准确的估计。

To do this you'd need to work out the reciprocal using some method, for example, Newton-Raphson which uses Newton's method to calculate successively more accurate estimates of the reciprocal of the divisor until it's "adequately" accurate for your purpose before doing the final multiplication step.

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