php-数组的深度搜索数组，仅返回匹配的元素 [英] php - deep search array of arrays and return only matching elements
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问题描述
我正在寻找php中的解决方案，如对此问题的公认答案所述:
I am looking for a solution in php as mentioned in the accepted answer of this question:
javascript-返回父级，只有一个子级，该子级与具有嵌套对象的对象数组中的给定搜索字符串匹配
请找到以下代码:
<?php
$items = array(
'tableData' => array
(
array
(
'booking_name' => 'abc/xyz/123',
'pdg' => 'assure',
'user_area' => 'es st1',
'release' => 'oss72',
'start_date' => '2017-06-20 00:00:00',
'end_date' => '2017-06-23 00:00:00',
'asset_info' => array
(
array
(
'status' => 10,
'manufacturer' => 'Oracle',
'model' => 'HP BL460C GEN8',
'hardware_color' => '#0066b3',
),
array
(
'status' => 11,
'manufacturer' => 'HP',
'model' => 'HP BL460C GEN81',
'hardware_color' => '#0066b3',
)
),
'full_name' => 'Valay Desai',
'email_address' => 'valay@xyz.com',
),
array
(
'booking_name' => 'abc/xyz/123',
'pdg' => 'enm',
'user_area' => 'es st',
'release' => 'oss72',
'start_date' => '2017-06-20 00:00:00',
'end_date' => '2017-06-23 00:00:00',
'asset_info' => array
(
array
(
'status' => 10,
'manufacturer' => 'HP',
'model' => 'HP BL460C GEN8',
'hardware_color' => '#0066b3',
)
),
'full_name' => 'Valay Desai',
'email_address' => 'valay@xyz.com',
)
)
);
function getParentStackComplete($child, $stack) {
$return = array();
foreach ($stack as $k => $v) {
if (is_array($v)) {
// If the current element of the array is an array, recurse it
// and capture the return stack
$stack = getParentStackComplete($child, $v);
// If the return stack is an array, add it to the return
if (is_array($stack) && !empty($stack)) {
$return[] = $v;
}
} else {
// Since we are not on an array, compare directly
if(strpos($v, $child) !== false){
// And if we match, stack it and return it
$return[] = $v;
}
}
}
// Return the stack
return empty($return) ? false: $return;
}
echo "<pre>";
print_r(getParentStackComplete('Oracle', $items['tableData']));
echo "</pre>";
?>
此代码可以正常工作.我在线找到了功能getParentStackComplete，对其进行了修改以返回整个匹配元素.它递归搜索数组并返回匹配项.
This code works fine. I found the function getParentStackComplete online, modified it to return the whole matching element. It search the array recursively and return matching items.
例如，如代码中所给的，如果我搜索字符串'Oracle'，则它应返回一个数组，其中只有一项在asset_info中只有一个子级(匹配元素).我正在寻找的输出是:
For example, as given in the code, If I search for a string 'Oracle', it should return an array with one item which has only one child(matching element) in asset_info. The output I am looking for is:
Array
(
[0] => Array
(
[booking_name] => abc/xyz/123
[pdg] => assure
[user_area] => es st1
[release] => oss72
[start_date] => 2017-06-20 00:00:00
[end_date] => 2017-06-23 00:00:00
[asset_info] => Array
(
[0] => Array
(
[status] => 10
[manufacturer] => Oracle
[model] => HP BL460C GEN8
[hardware_color] => #0066b3
)
)
[full_name] => Valay Desai
[email_address] => valay@xyz.com
)
)
如果我搜索字符串HP BL460C GEN8，它应该返回如下:
If I search for a string HP BL460C GEN8, it should return as below:
Array
(
[0] => Array
(
[booking_name] => abc/xyz/123
[pdg] => assure
[user_area] => es st1
[release] => oss72
[start_date] => 2017-06-20 00:00:00
[end_date] => 2017-06-23 00:00:00
[asset_info] => Array
(
[0] => Array
(
[status] => 10
[manufacturer] => Oracle
[model] => HP BL460C GEN8
[hardware_color] => #0066b3
)
)
[full_name] => Valay Desai
[email_address] => valay@xyz.com
)
[1] => Array
(
'booking_name' => 'abc/xyz/123',
'pdg' => 'enm',
'user_area' => 'es st',
'release' => 'oss72',
'start_date' => '2017-06-20 00:00:00',
'end_date' => '2017-06-23 00:00:00',
'asset_info' => array
(
array
(
'status' => 10,
'manufacturer' => 'HP',
'model' => 'HP BL460C GEN8',
'hardware_color' => '#0066b3',
)
),
'full_name' => 'Valay Desai',
'email_address' => 'valay@xyz.com'
)
)
如何在嵌套数组搜索中返回与父项匹配的子项?
推荐答案
尝试以下代码.
function getParentStackComplete( $search, $stack ){
$results = array();
foreach( $stack as $item ){
if( is_array( $item ) ){
if( array_filter($item, function($var) use ($search) { return ( !is_array( $var ) )? stristr( $var, $search ): false; } ) ){
//echo 'test';
$results[] = $item;
continue;
}else if( array_key_exists('asset_info', $item) ){
$find_assets = array();
foreach( $item['asset_info'] as $k=>$v ){
//echo 'abc ';
if( is_array( $v ) && array_filter($v, function($var) use ($search) { return stristr($var, $search); }) ){
$find_assets[] = $v;
}
}
if( count( $find_assets ) ){
$temp = $item;
$temp['asset_info'] = $find_assets;
$results[] = $temp;
}
}
}
}
return $results;
}
这篇关于php-数组的深度搜索数组，仅返回匹配的元素的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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