用字符串中的HTML链接替换类似Markdown的链接 [英] Replace Markdown-like links with HTML links in a string

问题描述

我有一个字符串形式

"Look at this [website]{http://www.stackoverflow.com} 
or at this [page]{http://www.google.com}"

我想用PHP解析它们

"Look at this <a href='http://wwwstackoverflow.com'>website</a> 
or at this <a href='http://www.google.com'>page</a>"

我该怎么做?

我虽然要使用str_replace()，但是我不知道如何在方括号[]之间获得字符串.

I though about using str_replace()but I dont know how to get the string between the brackets [].

编辑[26.08.2016] :答案使用带有正则表达式的PHP preg_replace方法.我在这里不明白给出的答案，但是它起作用了，所以我很高兴，但是现在我发现了这免费教程，该教程可以教您如何使用正则表达式.我发现它非常有帮助.尤其是当有人想为类似的情况写自己的正则表达式时.

Edit[26.08.2016]: The answer uses the PHP preg_replace method with Regular Expression. I didnt understand the given answer here, but it worked so I was happy But now I found this free tutorial that teaches you how to use Regular Expression. I found it very helpful. Especially when one wants to wrtie his own Regular Expression for a similar case.

推荐答案

尝试使用preg_replace

$str="Look at this [website]{http://www.stackoverflow.com} or at this [page]{http://www.google.com}";

echo preg_replace('/\[(.*?)\]\{(.*?)\}/', "<a href='$2'>$1</a>", $str);

输出:

Look at this <a href='http://www.stackoverflow.com'>website</a> or at this <a href='http://www.google.com'>page</a>

工作示例: https://3v4l.org/jLbff

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