如何用html文档中的超链接替换原始网址 [英] how to replace plain url with hyperlinks in html doc

问题描述

我试图在HTML文档中替换纯链接到超链接。
和我的逻辑是
$ b $ pre $ private static final Pattern WEB_URL_PROTOCOL = Pattern.compile（（？i）http | https ：//）;

StringBuffer sb = new StringBuffer（）;
if（text！= null）{
//在文本消息中转义任何无意的HTML
text = EmailHtmlUtil.escapeCharacterToDisplay（text）;
//查找任何嵌入的URL并链接
Matcher m = Patterns.WEB_URL.matcher（text）;


while（m.find（））{
int start = m.start（）;

if（start == 0 || text.charAt（start - 1）！='@'）{
String url = m.group（）;
Matcher proto = WEB_URL_PROTOCOL.matcher（url）;
字符串链接;
if（proto.find（））{
小写协议链接。
link = proto.group（）。toLowerCase（）+ url.substring（proto.end（））;
} else {

link =http：//+ url;
}
String href = String.format（< a href = \％s \>％s< / a>，link，url）;
m.appendReplacement（sb，href）;
}
else {
m.appendReplacement（sb，$ 0）;
}
}
m.appendTail（sb）;
}


此代码成功找出html文档中的所有链接，但问题是它也可以找到超链接。所以我想排除超链接并且只想找到简单的链接
，例如它应该排除

 < p class =MsoNormal>< a href =awbs：//www.google.comtarget =_BLANK> https：//www.google.com< / a>普通地址https< / p> 
  

但简单链接 https://www.google.com -
1. 应该被一个超链接替换
//www.yahoo.comrel =nofollow> https://www.yahoo.com

2. https://www.google.com 正常地址https

所以在这里我想替换 https://www.yahoo.com with

 < p class =MsoNormal>< a href =https：//www.yahoo.com> https：//www.yahoo.com< / a>< / p> 
  
 
 
 
，它应该不会影响2。 
 
解决方案
我会建议您在这里使用 jsoup 。
 
 
 
示例代码
 
 
 
  String text =< html>< head>< / head> ;< body>< a href ='http：//google.com '>请勿更改此链接< / a>更改此：http://yahoo.com foo.com< / body>< / html>; 
 Document d = Jsoup.parse（text）; 
 String newHtmlCode =; 
 String oldHtmlCode = d.outerHtml（）; 
 List< TextNode> textNodes = d.body（）。textNodes（）; 
 
 Matcher m = Patterns.WEB_URL.matcher（ ）; 
 for（TextNode textNode：textNodes）{
 m.reset（textNode.text（））; 
 
 String fragment =; 
 while（m .find（））{
 fragment = m.replaceAll（< a href = \\\ * \\ * \\ * $ 1 \> $ 1< / （b））; 
 textNode.replaceWith（新元素d.outerHtml（）。replaceAll（\\\ Q *** \\E（？！https？：//），\http：//）.replaceAll（ \\\\ Q *** \\E（https？：//），\$ 1）; 
} 
 
 System.out。 println（BEFORE：\\\
\\\
+ oldHtmlCode）; 
 System.out.println（----------------------- -----）; 
 System.o ut.println（AFTER：\\\
\\\
+ newHtmlCode）; 
  
 
 
 
 h3> 
 
 
 之前：
 
< html> 
< head>< / head> 
< body> 
< a href =http://google.com>不要更改此链接< / a>更改此：http://yahoo.com foo.com 
< / body> 
< / html> 
 ---------------------------- 
 AFTER：
 
< html> 
< head>< / head> 
< body> 
< a href =http://google.com>不要更改此链接< / a> 
< span>更改此项：< a href =http://yahoo.com> http：//yahoo.com< / a> < a href =http://foo.com> foo.com< / a>< / span> 
< / body> 
< / html> 
  
 
I am trying to replace plain link to hyperlink in an html document.
and my logic is 
private static final Pattern WEB_URL_PROTOCOL = Pattern.compile("(?i)http|https://");

StringBuffer sb = new StringBuffer();
        if (text != null) {
            // Escape any inadvertent HTML in the text message
            text = EmailHtmlUtil.escapeCharacterToDisplay(text);
            // Find any embedded URL's and linkify
              Matcher m = Patterns.WEB_URL.matcher(text);


            while (m.find()) {
                int start = m.start();

                if (start == 0 || text.charAt(start - 1) != '@') {
                    String url = m.group();
                    Matcher proto = WEB_URL_PROTOCOL.matcher(url);
                    String link;
                    if (proto.find()) {
                        lower case protocol link.
                        link = proto.group().toLowerCase() + url.substring(proto.end());
                    } else {

                        link = "http://" + url;
                    }
                    String href = String.format("<a href=\"%s\">%s</a>", link, url);
                    m.appendReplacement(sb, href);
                }
                else {
                    m.appendReplacement(sb, "$0");
                }
            }
            m.appendTail(sb);
        }
This code is successfully find out all links in a html doc .but problem is it also find the hyperlink.So i want to exclude the hyperlinks and want to find only plain links 
for example it should exclude 
<p class="MsoNormal"><a href="awbs://www.google.com" target="_BLANK">https://www.google.com</a> normal address https</p> 
but plain link https://www.google.com  should be replaced by a hyperlink

Edit
if doc contain text like this - 
1. https://www.yahoo.com
 
2. https://www.google.com normal address https


so here i want to replace  https://www.yahoo.com with 
<p class="MsoNormal"><a href = "https://www.yahoo.com>https://www.yahoo.com</a></p>
and it should not effect 2 at all . 
解决方案
I would recommand you to use Jsoup here.

Sample code

String text = "<html><head></head><body><a href='http://google.com'>Don't change this link</a> Change this: http://yahoo.com foo.com</body></html>";
Document d = Jsoup.parse(text);
String newHtmlCode = "";
String oldHtmlCode = d.outerHtml();
List<TextNode> textNodes = d.body().textNodes();

Matcher m = Patterns.WEB_URL.matcher("");
for (TextNode textNode : textNodes) {
    m.reset(textNode.text());

    String fragment = "";
    while (m.find()) {
        fragment = m.replaceAll("<a href=\"\\*\\*\\*$1\">$1</a>");
        textNode.replaceWith(new Element(Tag.valueOf("span"),"").html(fragment));
    }

    newHtmlCode = d.outerHtml().replaceAll("\"\\Q***\\E(?!https?://)", "\"http://").replaceAll("\"\\Q***\\E(https?://)", "\"$1");
}

System.out.println("BEFORE:\n\n" + oldHtmlCode);
System.out.println("----------------------------");
System.out.println("AFTER:\n\n" + newHtmlCode);


Output

BEFORE:

<html>
 <head></head>
 <body>
  <a href="http://google.com">Don't change this link</a> Change this: http://yahoo.com foo.com
 </body>
</html>
----------------------------
AFTER:

<html>
 <head></head>
 <body>
  <a href="http://google.com">Don't change this link</a>
  <span> Change this: <a href="http://yahoo.com">http://yahoo.com</a> <a href="http://foo.com">foo.com</a></span>
 </body>
</html>


                        
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