在没有超链接的地方用超链接替换文本 [英] Replace text with hyperlinks where there isn't already one

问题描述

一个更好的例子是:

$string = "That is a very nice ford mustang, if only every other ford was quite as nice as this honda";

如果汽车名称匹配，我想用制造商和型号的链接替换汽车名称，或者只是制造商，但是如果有品牌和型号，它会将链接放在链接中，例如，如果您使用 str 替换....

I want to replace the car names with a link for manufacturer and model if they match, or just manufacturer, but if there is a make and model it puts links within links if you use str replace for example....

$remove = array("ford mustang","ford","honda");
$replaceWith = array("<a href='fordID'>ford</a>","<a href='fordmustangID'>ford mustang</a>","<a href='hondaID'>honda</a>");

结果如下:

"That is a very nice <a href='<a href='fordmustangID'>ford mustang</a>ID'><a href='fordmustangID'>ford mustang</a></a>, if only every other <a href='fordmustangID'>ford mustang</a> was quite as nice as this <a href='hondaID'>honda</a>"

如果没有这样的超链接，我只希望它创建一个超链接:

I only want it to create a hyperlink if there isn't one already like this:

  "That is a very nice <a href='fordmustangID'>ford mustang</a>, if only every other <a href='fordID'>ford</a> was quite as nice as this <a href='hondaID'>honda</a>"

推荐答案

edit:

花了我很长时间，但这是我想出的:

edit:

Took me a good while, but here's what I came up with:

function replaceLinks($replacements, $string){
    foreach($replacements as $key=>$val){
        $key=strtolower((string)$key);
        $newReplacements[$key]=array();
        $newReplacements[$key]['id']=$val;
        //strings to make sure the search isn't in front of
        $newReplacements[$key]['behinds']=array();
        //strings to make sure the search isn't behind
        $newReplacements[$key]['aheads']=array();
        //check for other searches this is a substring of
        foreach($replacements as $key2=>$val2){
            $key2=(string)$key2;
            /* 
            //debugging
            $b = ($key=='11 22'&&$key2=='11 22 33');
            if($b){
                l('strlen $key2: '.strlen($key2));
                l('strlen $key: '.strlen($key));
                l('strpos: '.(strpos($key2,$key)));

            }
            */
            //the second search is longer and the first is a substring of it
            if(strlen($key2)>strlen($key) && ($pos=strpos($key2,$key))!==false){
                //the first search isn't at the start of the second search ('the ford' and 'ford')
                if($pos!=0){
                    $newReplacements[$key]['behinds'][]=substr($key2,0,$pos);
                }
                //it's not at the end ('ford' and 'fords')
                if(($end=$pos+strlen($key))!=strlen($key2)){
                    $newReplacements[$key]['aheads'][]=substr($key2,$end);
                }
            }
        }
    }
    foreach($newReplacements as $key=>$item){
        //negative lookbehind for words or >
        $tmp="/(?<![\w>=])";
        //negative lookbehinds for the beginnings of other searches that this search is a subtring of
        foreach($item['behinds'] as $b){
            $tmp.="(?<!$b)";
        }
        //the actual search
        $tmp.="($key)";
        //negative lookaheads for ends of other searches that this is a substring of.
        foreach($item['aheads'] as $a){
            $tmp.="(?!$a)";
        }
        //case insensitive
        $tmp.='/ie';
        $replacementMatches[]=$tmp;
    }
    return preg_replace($replacementMatches,'"<a href=\"".$newReplacements[strtolower("$1")]["id"]."\">$1</a>"' ,$string);

}

将一个数组传递给它，例如您正在谈论的那个:

Pass it an array such as the one you were talking about:

$replaceWith = array('ford mustang'=>123,'ford'=>42,'honda'=>324);

和一个字符串:

$string = "That is a very nice ford mustang, if only every other ford was quite as nice as this honda";

echo replaceLinks($replaceWith,$string);

它优先考虑较大的字符串键，因此如果您有 ford 和 ford mustang，它将用链接替换 ​​ford mustang.

It gives precedence to larger string keys, so if you have ford and ford mustang, it will replace ford mustang with the link.

不太实用，但可能有用.

Not very practical, but might work.

$string = "That is a very nice ford mustang, if only every other ford was quite as nice as this honda";
$remove = array("/(?<![\w>])ford mustang(?![\w<])/",'/(?<![>\w])ford(?! mustang)(?![<\w])/',"/(?<![>\w])honda(?![<\w])/");
$replaceWith = array("<a href='fordmustangID'>ford mustang</a>","<a href='fordID'>ford</a>","<a href='hondaID'>honda</a>");
echo preg_replace($remove, $replaceWith,$string);

我使用带有负前瞻和后视的正则表达式来确保我们要替换的字符串部分不是字母数字序列的一部分(如 12ford23 或 afford>) 或触摸元素的开始或结束标记.

I used regular expressions with negative lookaheads and lookbehinds to make sure the portion of the string we're replacing isn't part of an alphanumeric sequence (like 12ford23 or afford) or touching the start or end tag of an element.

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