如何从字符串中删除PHP代码? [英] How to remove php code from a string?

问题描述

我有一个包含php代码的字符串，我需要从该字符串中删除php代码，例如:

I have a string that has php code in it, I need to remove the php code from the string, for example:

<?php $db1 = new ps_DB() ?><p>Dummy</p>

应返回<p>Dummy</p>

并且没有php的字符串(例如<p>Dummy</p>)应返回相同的字符串.

And a string with no php for example <p>Dummy</p> should return the same string.

我知道可以使用正则表达式来完成此操作，但是4小时后我还没有找到解决方法.

I know this can be done with a regular expression, but after 4h I haven't found a solution.

推荐答案

 <?php
 function filter_html_tokens($a){
    return is_array($a) && $a[0] == T_INLINE_HTML ?
      $a[1]:
      '';
 }
 $htmlphpstring = '<a>foo</a> something <?php $db1 = new ps_DB() ?><p>Dummy</p>';
 echo implode('',array_map('filter_html_tokens',token_get_all($htmlphpstring)));
 ?>

---

ircmaxell指出:这将需要有效的PHP！

---

As ircmaxell pointed out: this would require valid PHP!

正则表达式的路由是(不允许在字符串/文件中使用短标签的'php'.没有结束符?>(出于某种原因，Zend推荐这样做?)，当然还有一个UNgreedy&DOTALL模式:

A regex route would be (allowing for no 'php' with short tags. no ending ?> in the string / file (for some reason Zend recommends this?) and of course an UNgreedy & DOTALL pattern:

preg_replace('/<\\?.*(\\?>|$)/Us', '',$htmlphpstring);

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