PHP 从字符串中删除终端代码 [英] PHP remove terminal codes from string

问题描述

在处理使用 proc_open 创建的进程的输入/输出时，我遇到了特殊的终端 ANSI 代码 (\033[0J,\033[13G)，除了没有找到这些特定代码正在做什么的参考之外，它们真的搞乱了我的 preg_match 调用.

While processing the input/output of a process created with proc_open, I've been hit with the special terminal ANSI codes (\033[0J,\033[13G), aside from not finding a reference to what these particular codes are doing, they are really messing with my preg_match calls.

PHP 是否有内置的方法来清理这些类型的字符串?或者与 preg_replace 一起使用的正确表达式是什么?请注意，我正在处理非 ascii 字符，因此剥离除...之外的所有内容都不起作用.

Does PHP have a built in method for cleansing these types of strings? Or what would be the correct expression to use with preg_replace? Please note, I am dealing with non ascii characters, so stripping everything except... will not work.

推荐答案

通常 ANSI 代码是由 ESC (\033 aka \x1b) 引入的，一个空心方块括号，然后是数字(可能重复:*[32;40m)并以字母结尾.

Usually ANSI codes are introduced by an ESC (\033 aka \x1b), an open square bracket, then numbers (possibly repeated: *[32;40m) and terminated by a letter.

你可以使用类似 #\\x1b[[][0-9]+(;[0-9]*)[A-Za-z]# 到 preg_replace 他们都被遗忘了.

You can use something like #\\x1b[[][0-9]+(;[0-9]*)[A-Za-z]# to preg_replace them all to oblivion.

这有效(刚刚测试)，即使绝对是矫枉过正:

This works (just tested), even if definitely overkill:

$test = preg_replace('#\\x1b[[][^A-Za-z]*[A-Za-z]#', '', $test);

我也在 GitHub 上找到了这个，和 此内容.

I've also found this on GitHub, and this on SO.

这篇关于PHP 从字符串中删除终端代码的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！