PHP:如何在模态URL中放置和传递变量 [英] PHP : How to put and pass variable in modal URL

问题描述

因此，我有一个按钮可以直接链接到同一页面中的模式.

So, I have a button to give a direct link to modal in same page.

这是按钮和网址

<a data-toggle="modal" 
   href="main_user.php?user_id=<?php echo $user['user_id']; ?>#myModal" 
   class="btn btn-warning">

(我尝试在#modal之前回显$user_id)对吗?

( I try to echo the $user_id on before #modal ) is it right ?

，然后单击按钮，将出现模态. 这是具有形式的模态.

and after I click the button, the modal will appear. This is the modal with the form.

<form class="form-login" action="action/doEditUserStatus.php" method="post">
          <div class="login-wrap">
               <div class="changestatus">
                   <p>Banning or Activing User Status</p></div>
                        <div class="btn-group" data-toggle="buttons">
                            <label class="btn btn-success active">
                               <input type="radio" name="options" value="1" autocomplete="off"  checked> Actived
                            </label>
                            <label class="btn btn-primary">
                              <input type="radio" name="options" value="2" autocomplete="off"> Banned
                            </label>
                        </div>
          </div>
           <div class="modal-footer">
                <button data-dismiss="modal" class="btn btn-default" type="button">Cancel</button>
                <button class="btn btn-theme" name="modalSubmit" type="submit">Submit</button>
           </div>
    </form>

然后我尝试提交模式表格，但是该操作无法读取我在#modal之前放置的$user_id.

And then I try to submit the modal form, but the action cannot read the $user_id which I put before #modal.

更新: 表格代码:

这是我的桌子:

<tr class="success">
   <th class="numeric">ID</th>
   <th class="numeric">E-mail</th>
   <th class="numeric">Name</th>
   <th class="numeric">Phone</th>
   <th class="numeric">Picture</th>
   <th class="numeric">Status</th>
   <th colspan="2" class="numeric">Action</th>
</tr>


<tr>
   <td class="numeric"><?php echo $user['user_id']; ?></td>
   <td class="numeric"><?php echo $user['email']; ?></td>
   <td class="numeric"><?php echo $user['name']; ?></td>
   <td class="numeric"><?php echo $user['phone']; ?></td>
   <td class="numeric"><?php echo $user['picture']; ?></td>
   <td class="numeric">
       <a data-toggle="modal" href="main_user.php?user_id=<?php echo $user['user_id']; ?>#myModal" class="btn btn-warning">
          <span class="glyphicon glyphicon-edit" aria-hidden="true"></span>&nbsp;Change Status
        </a>
   </td>
</tr>

主要问题是: 当我单击按钮时，将出现模态，但无法从该按钮获取$user_id?

The main problem is : When I click the button, then the modal will appear but it can't get the $user_id from that button?

推荐答案

将带有user_id的隐藏输入字段放入表单:

Put a hidden input field with the user_id into your form:

<input type="hidden" name="user_id" value="<?php echo $user['user_id']; ?>">

---

如果您的意思是Bootstrap，请尝试以下操作:

---

If you mean Bootstrap try this:

链接/按钮:

<a data-toggle="modal" data-userid="<?php echo $user['user_id']; ?>"
   href="main_user.php#myModal" 
   class="btn btn-warning">

隐藏表单字段:

<input type="hidden" name="user_id" value="">

JavaScript:

Javascript:

$('#myModal').on('show.bs.modal', function(e) {
    var userid = $(e.relatedTarget).data('userid');
    $(e.currentTarget).find('input[name="user_id"]').val(userid);
});

另请参见 http://getbootstrap.com/javascript/#modals-related-target 和将数据传递到引导程序模式

您应该在问题中提到Bootstrap. PHP不是适当的标记.

You should have mentioned Bootstrap in your question. PHP is not the appropriate tag.

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