包含特殊字符的任何英文ASCII字符的正则表达式 [英] Regex for Any English ASCII Character Including Special Characters

问题描述

我想用php写一个正则表达式，使其仅匹配任何英文字符，空格，数字和所有特殊字符.

I want to write a regex in php to match only any english characters, spaces, numbers and all special chars.

从这个问题 对任意ascii字符进行正则

我尝试过

preg_match("/[\x00-\x7F]+/", $str);

但它会发出警告

No ending delimiter '/' found 

因此，如何在php中编写此正则表达式.

so, how to write this regex in php.

替代方法可能像[a-z \ d \ s]这样，也可以一一考虑所有特殊字符，但是没有办法做得更简单吗?

the alternative would be smth like [a-z\d\s] and also one by one consider all special chars, but is not there a way to do simpler ?

谢谢

推荐答案

有许多复杂的解决方案，但我建议使用这种非常简单的正则表达式:

There are a number of intricate solutions, but I would suggest this beautifully simple regex:

^[ -~]+$

它允许 ASCII表中的所有可打印字符.

It allows all printable characters in the ASCII table.

在PHP中:

$regex = '%^[ -~]+$%';
if (preg_match($regex, $yourstring, $m)) {
    $thematch = $m[0];
    } 
else { // no match...
     }

说明

• ^锚断言我们在字符串的开头
• 字符类[ -~]匹配空格和波浪号之间的所有字符(ASCII表中的所有可打印字符)
• +量词的意思是匹配其中一个或多个"
• $锚断言我们在字符串的末尾

• The ^ anchor asserts that we are at the beginning of the string
• The character class [ -~] matches all characters between the space and the tilde (all the printable characters in the ASCII table)
• The + quantifier means "match one or more of those"
• The $ anchor asserts that we are at the end of the string

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