（grep）正则表达式匹配非ASCII字符？ [英] (grep) Regex to match non-ASCII characters?

问题描述

在Linux上，我有一个包含大量文件的目录。其中一些具有非ASCII字符，但它们都是有效的 UTF-8 。一个程序有一个错误，可以防止它使用非ASCII文件名，我必须找出有多少人受到影响。我打算用 find 来做到这一点，然后做一个 grep 打印非ASCII字符，然后执行 wc -l <​​/ code>来查找编号。它不一定是grep;我可以使用任何标准的Unix 正则表达式，如 Perl ， sed ， AWK 等。

然而， ，是否有'任何不是ASCII字符的字符'的正则表达式？

解决方案

这将匹配单个非ASCII字符：

  [^ \x00-\x7F] 
  

这是一个有效的 PCRE （ Perl兼容正则表达式）。

您也可以使用 POSIX shorthands：

• [[：ascii：] ] - 匹配一首歌le ASCII字符


• [^ [：ascii：]] - 匹配单个非ASCII字符
  

---

[^ [：print：]] 只要你满意。**

On Linux, I have a directory with lots of files. Some of them have non-ASCII characters, but they are all valid UTF-8. One program has a bug that prevents it working with non-ASCII filenames, and I have to find out how many are affected. I was going to do this with find and then do a grep to print the non-ASCII characters, and then do a wc -l to find the number. It doesn't have to be grep; I can use any standard Unix regular expression, like Perl, sed, AWK, etc.

However, is there a regular expression for 'any character that's not an ASCII character'?

解决方案

This will match a single non-ASCII character:

[^\x00-\x7F]

This is a valid PCRE (Perl-Compatible Regular Expression).

You can also use the POSIX shorthands:

• [[:ascii:]] - matches a single ASCII char
• [^[:ascii:]] - matches a single non-ASCII char

---

[^[:print:]] will probably suffice for you.**

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