正则表达式非连续字符 [英] Regex non-consecutive chars

问题描述

目前我有:

[A-Za-z0-9._%+-]

这匹配任何包含字母、数字和某些特殊字符 (._%+-) 的字符串

This matches any string that contains letters, numbers, and certain special chars (._%+-)

如何更改它以使其不匹配连续包含特殊字符的字符串?

How can I change this so that it won't match a string that contains the special chars consecutively?

例如，我希望它匹配:foo.bar+test 和 foo.+bar 和 +foo.

For example, I want it to match: foo.bar+test and foo.+bar and +foo.

但不是:foo..bar+test 或 foo.bar++test 或 foo.bar++

推荐答案

如果您的工具/语言支持前瞻，请尝试:

If your tool/language supports look aheads, try:

^(?!.*([._%+-])\1)[A-Za-z0-9._%+-]+$

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