如何使用Swift生成(10 ... 20)范围内的随机数 [英] How to generate a random number in a range (10...20) using Swift

问题描述

我可以为游戏中的物品选择一个随机数，但 是否可以从2个数字之间选择一个随机数?

I'm able to pick a random number for my items in my game but is it possible to pick a random number between 2 numbers?

所以而不是

let number = (arc4random_uniform(100))

我想要这样的东西:

let number = (arc4random_uniform(10...20))

还是类似的东西? 现在，如果我得到了放下武器的信息，那么它可能就是清单中的所有内容. 通过这种方式，我可以做到，只有前几个怪物会掉落特定的怪物，或者在更高级别时，他们会掉落更好的武器，而不再是低水平的武器.

or something like that? Now if I get a weapon drop it can be everything in my list. This way I could make it so that only the first few would have a drop for a specific monster or at higher level they would drop better weapons and not the low levels anymore.

推荐答案

Xcode 11•Swift 5.1或更高版本

extension Range where Bound: FixedWidthInteger {
    var random: Bound { .random(in: self) }
    func random(_ n: Int) -> [Bound] { (0..<n).map { _ in random } }
}

---

extension ClosedRange where Bound: FixedWidthInteger  {
    var random: Bound { .random(in: self) }
    func random(_ n: Int) -> [Bound] { (0..<n).map { _ in random } }
}

注意:对于较早的Swift版本，请检查编辑历史记录

Note: For older Swift versions check the edit history

用法:

(10...20).random    // 16
(0...1).random(10)  // [0, 1, 0, 0, 1, 1, 1, 1, 1, 0]

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