C ++排除范围内的随机数 [英] C++ Random number within range with exclusion

问题描述

我想生成范围从0到5的随机数，但是例如，在某些情况下，我不需要数字3，我只需要0,1,2,4,5。如何生成随机数

I want to generate random number in range from 0 to 5, but for example, in some cases I don't need number 3, I only need 0, 1, 2, 4, 5. How can I generate random number within range, but with option to exclude numbers I don't need.

推荐答案

是否要在编译时排除已知的数字时间？然后一个简单的查找表应该：

Are the numbers you want to exclude known at compile time? Then a simple lookup table should do:

static int table[] = {0, 1, 2, 4, 5};
int index = rand() % (sizeof table / sizeof *table);
int number = table[index];

当然， rand（）可怕的伪随机数生成器，但这是一个不同的主题。

Of course, rand() is a terrible pseudo random number generator, but that's a different topic.

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