如何制作长度为5的数字和字母的随机字符串? [英] How to make random string of numbers and letters with a length of 5?

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问题描述

可能重复:
这是生成广告活动的好方法一串随机字符?
如何生成随机的8个字符的字母数字字符串在C#中?

Possible Duplicate:
Is this a good way to generate a string of random characters?
How can I generate random 8 character, alphanumeric strings in C#?

这是我到目前为止的代码.

This is the code that I have so far.

    private void button1_Click(object sender, EventArgs e)
    {
        string rand1 = RandomString(5);
        string rand2 = RandomString(5);
        string rand3 = RandomString(5);
        string rand4 = RandomString(5);
        string rand5 = RandomString(5);
        textBox1.Text = rand1 + "-" + rand2 + "-" + rand3 + "-" + rand4 + "-" + rand5;

    }
    private static Random random = new Random((int)DateTime.Now.Ticks);
    private string RandomString(int Size)
    {
        StringBuilder builder = new StringBuilder();
        char ch;
        for (int i = 0; i < Size; i++)
        {
            ch = Convert.ToChar(Convert.ToInt32(Math.Floor(26 * random.NextDouble() + 65)));
            builder.Append(ch);
        }
        return builder.ToString();
    }

但是它只是创建一个随机的5个字符的字符串. 我希望它创建5个字符和整数的字符串. 我该怎么做?提前致谢!

BUT it just creates a random string of 5 chars. I want it to create a string of 5 chars and integers. How would I do this? Thanks in advance!

推荐答案

使用输入数组从以下位置绘制值:

Use an input array to draw your values from:

private static string RandomString(int length)
{
    const string pool = "abcdefghijklmnopqrstuvwxyz0123456789";
    var builder = new StringBuilder();

    for (var i = 0; i < length; i++)
    {
        var c = pool[random.Next(0, pool.Length)];
        builder.Append(c);
    }

    return builder.ToString();
}

或(不可避免的)Linq解决方案:

Or the (inevitable) Linq solution:

private static string RandomString(int length)
{
    const string pool = "abcdefghijklmnopqrstuvwxyz0123456789";
    var chars = Enumerable.Range(0, length)
        .Select(x => pool[random.Next(0, pool.Length)]);
    return new string(chars.ToArray());
}

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