有没有更短的方法来初始化QByteArray? [英] Is there a shorter way to initialize a QByteArray?
问题描述
在我的程序中,我经常进行串行通信,因此QByteArray
经常使用.
In my program I work a lot with serial communication so QByteArray
is used very often.
我想知道是否有比使用以下特定字节初始化QByteArray
的短方法:
I was wondering if there was a shorter way to initialize a QByteArray
with specific bytes than:
const char test_data[] = {
static_cast<char>(0xB1), static_cast<char>(0xB2),
0x5, static_cast<char>(0xFF),
static_cast<char>(0xEE), static_cast<char>(0xEE),
static_cast<char>(0x0)}; // Note QByteArray should be able to hold 0 byte
const QCanBusFrame frame = QCanBusFrame(0xA1, QByteArray(test_data));
static_cast<char>
是必需的,因为否则C ++ 11会给出有关缩小的错误,因为0x7F到0xFF的范围大于char
的范围,但是char
是QByteArray
构造函数要求.
The static_cast<char>
is necessary because otherwise C++11 gives an error about narrowing, because the range 0x7F to 0xFF is bigger than a char
could fit--but a char
is what the QByteArray
constructor asks for.
这是正在使用的QByteArray
构造函数:
This is the QByteArray
constructor being used:
QByteArray::QByteArray(const char *data, int size = -1)
推荐答案
受到以上答案的启发,我终于想到了:
Being inspired by the answers above this is what I finally came up with:
const quint8 testData[] {0xB1, 0x00, 0xB2, 0x00};
const QCanBusFrame cFrame = QCanBusFrame(
0xA1, QByteArray(reinterpret_cast<const char*>(testData), sizeof(testData)));
在进行串行通信时,我更喜欢将字节作为字节数而不是文字字符.
I much prefer to have the bytes as byte numbers rather than literal characters when working with serial communication.
在## c ++讨论之后,我被告知在这种情况下应适当使用reinterpret_cast
.
After having a discussion on ##c++ I was advised that reinterpret_cast
is appropriately used in this situation.
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