如何使用Ruby或Nokogiri获取页面的原始HTML源代码? [英] How to get the raw HTML source code for a page by using Ruby or Nokogiri?
问题描述
我正在使用 Nokogiri (Ruby Xpath库)在网页上grep内容.然后,我发现某些网页(例如Ajax网页)存在问题,这意味着当我查看源代码时,不会看到诸如<table>
等的确切内容.
I'm using Nokogiri (Ruby Xpath library) to grep contents on web pages. Then I found problems with some web pages, such as Ajax web pages, and that means when I view source code I won't be seeing the exact contents such as <table>
, etc.
如何获取实际内容的HTML代码?
How can I get the HTML code for the actual content?
推荐答案
如果您想要网页的原始资源,请不要使用Nokogiri.只需直接以字符串形式获取网页,然后不要将其提供给Nokogiri.例如:
Don't use Nokogiri at all if you want the raw source of a web page. Just fetch the web page directly as a string, and then do not feed that to Nokogiri. For example:
require 'open-uri'
html = open('http://phrogz.net').read
puts html.length #=> 8461
puts html #=> ...raw source of the page...
另一方面,如果您想要页面的JavaScript修改后内容(例如,执行JavaScript代码以获取新内容并更改页面的AJAX库),则不能使用Nokogiri.您需要使用Ruby来控制网络浏览器(例如,在Selenium或Watir上阅读).
If, on the other hand, you want the post-JavaScript-modified contents of a page (such as an AJAX library that executes JavaScript code to fetch new content and change the page), then you can't use Nokogiri. You need to use Ruby to control a web browser (e.g. read up on Selenium or Watir).
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