从googlechrome扩展中获取页面的源代码 [英] Getting the source code of a page from a googlechrome extension
问题描述
我正在写一份googlechrome的扩展程序，以显示网站中的项目列表。我遇到的问题是我无法获得我正在寻找的页面的源代码。当我尝试将它放入一个iframe中时，它的代码会改变窗口的位置。 XMLhttpRequest也只允许在你自己的域中。有没有什么办法可以通过JavaScript从googlechrome扩展中获取网站的源代码？
这里是清单：
{
name：My First Extension，
version：1.0，
description： ，
browser_action：{
default_icon：icon.png，
popup：popup.html
} ，
权限：[
http://api.flickr.com/，
http://search.twitter.com/
]
详细介绍此处。长话短说：
- 在清单中声明域权限。 后台页面。
- 使用消息传递，如果需要的话。
更新
以下代码适用于我：
清单 - 与您的完全一致。
popup.html：
< html>
< head>
< script>
var xhr = new XMLHttpRequest（）;
xhr.onreadystatechange = function（）{
if（xhr.readyState == 4）{
alert（xhr.status）;
if（xhr.status == 200）{
alert（xhr.responseText）;
}
}
}
var url =http://search.twitter.com/trends/current.json?exclude=hashtags;
xhr.open（GET，url，true）;
xhr.send（）;
< / script>
< / head>
< body>< / body>
< / html>
I am writting an extension for googlechrome to display a list of items from a website. The problem I have is that I cannot get the source code of the page I am looking for. When I tried putting it in an iframe, it had code that would change the location of the window. XMLhttpRequest is also only allowed on your own domain. Is there any way I can get the source code for a site from a googlechrome extension through javascript?
here is the manifest:
{
"name": "My First Extension",
"version": "1.0",
"description": "The first extension that I made.",
"browser_action": {
"default_icon": "icon.png",
"popup": "popup.html"
},
"permissions": [
"http://api.flickr.com/",
"http://search.twitter.com/"
]
}
It's all described in details here. Long story short:
- Declare domain permissions in the manifest.
- Make cross-domain request from a background page.
- Transfer results to a content script using message passing, if needed.
UPDATE
Here is code that works for me:
Manifest - exactly as yours.
popup.html:
<html>
<head>
<script>
var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
if (xhr.readyState == 4) {
alert(xhr.status);
if (xhr.status == 200) {
alert(xhr.responseText);
}
}
}
var url = "http://search.twitter.com/trends/current.json?exclude=hashtags";
xhr.open("GET", url, true);
xhr.send();
</script>
</head>
<body></body>
</html>
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