按顺序创建重复值的顺序? [英] Create sequence of repeated values, in sequence?

问题描述

我需要一个重复的数字序列，即1 1 ... 1 2 2 ... 2 3 3 ... 3 etc.我实现的方式是:

I need a sequence of repeated numbers, i.e. 1 1 ... 1 2 2 ... 2 3 3 ... 3 etc. The way I implemented this was:

  nyear <- 20
  names <- c(rep(1,nyear),rep(2,nyear),rep(3,nyear),rep(4,nyear),
             rep(5,nyear),rep(6,nyear),rep(7,nyear),rep(8,nyear))

有效，但笨拙，显然扩展性不佳.

which works, but is clumsy, and obviously doesn't scale well.

如何依次将N个整数重复M次?

• 我尝试嵌套seq()和rep()，但这并不能完全满足我的要求.
• 我显然可以编写一个for循环来执行此操作，但是应该有一种固有的方法来执行此操作！

• I tried nesting seq() and rep() but that didn't quite do what I wanted.
• I can obviously write a for-loop to do this, but there should be an intrinsic way to do this!

推荐答案

您错过了rep()的each=参数:

R> n <- 3
R> rep(1:5, each=n)
 [1] 1 1 1 2 2 2 3 3 3 4 4 4 5 5 5
R> 

因此您的示例可以通过简单的方式完成

so your example can be done with a simple

R> rep(1:8, each=20)

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