如何在弹簧控制器中获取参数 [英] How to get parameter in spring controller

问题描述

如何将数组发送到ajax请求.这是我的代码技能是数组

How to send array to ajax request.Here is my code skills is array

var url= "/ajax/gDirectory/saveskills.htm";
                 $.ajax({
                    type: "POST",
                    data: {skills:skills},
                    url: url,
                    async: true,
                    success :skillsUI
                  }); 

Spring Controller如何在控制器中获取参数

Spring Controller How to get parameter in controller

 @RequestMapping(value="/ajax/gDirectory/saveskills.htm" ,method=RequestMethod.POST)
        public @ResponseBody String saveskills(HttpServletRequest request,@RequestParam String skills) {}

推荐答案

您可以使用@RequestBody注释代替@RequestParam.

You can use the @RequestBody annotation instead @RequestParam.

让我们假设您有一个名为"Skill"的类，该类具有与您的"skill" json对象相同的属性.

Let's suppose that you have a class called "Skill" that has the same attributes that your "skill" json object has.

@RequestMapping(value="/ajax/gDirectory/saveskills.htm" ,method=RequestMethod.POST)
        public @ResponseBody String saveskills(HttpServletRequest request, @RequestBody List<Skill> skills) {}

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