Java - SpringMVC - 在控制器中获取参数 [英] Java - SpringMVC - Get parameter in the controller

问题描述

我有一个问题是将对象持久存储到我的数据库中。
我有一个与Profil有多对一关系的用户。

I have a problem to persist an object into my database. I have a User with a many-to-one relation with a Profil.

我的JSP只是添加一个新用户。因此，JSP包含字段和带有所需profil的comboxBox。问题是，当我运行程序时，即使我在comboxBox中选择了一个profil，控制器中的属性user.profil也是NULL。

My JSP just add a new user. So, the JSP contains fields and a comboxBox with the profil wanted. The problem is, when I run the program, even if I selected a profil in the comboxBox, the property user.profil is NULL in the controller.

这是用户对象：

package com.app.model;

import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.ManyToOne;
import javax.persistence.Table;

@Entity
@Table(name="user")
public class User {

    private long id;
    private String firstname;
    private String lastname;
    private String login;
    private String password;
    private Profil profil;

    public User() {
    }

    /**
     * @param firstname
     * @param lastname
     * @param login
     * @param password
     * @param profil
     */
    public User(String firstname, String lastname, String login,
            String password, Profil profil) {
        this.firstname = firstname;
        this.lastname = lastname;
        this.login = login;
        this.password = password;
        this.profil = profil;
    }

    /**
     * Get User Id
     * 
     * @return long - User Id
     */
    @Id
    @Column(name="id", unique = true, nullable = false)
    public long getId() {
        return id;
    }

    /**
     * Set User Id
     * 
     * @param long - User Id
     */
    public void setId(long id) {
        this.id = id;
    }

    /**
     * Get User Firstname
     * 
     * @return String - User Firstname
     */
    @Column(name="firstname", unique = false, nullable = false)
    public String getFirstname() {
        return firstname;
    }

    /**
     * Set User Firstname
     * 
     * @param String - User Firstname
     */
    public void setFirstname(String firstname) {
        this.firstname = firstname;
    }

    /**
     * Get User Lastname
     * 
     * @return String - User Lastname
     */
    @Column(name="lastname", unique = false, nullable = false)
    public String getLastname() {
        return lastname;
    }

    /**
     * Set User Lastname
     * 
     * @param String - User Lastname
     */
    public void setLastname(String lastname) {
        this.lastname = lastname;
    }

    /**
     * @return the login
     */
    @Column(name="login", unique = true, nullable = false)
    public String getLogin() {
        return login;
    }

    /**
     * @param login the login to set
     */
    public void setLogin(String login) {
        this.login = login;
    }

    /**
     * @return the password
     */
    @Column(name="password", unique = false, nullable = false)
    public String getPassword() {
        return password;
    }

    /**
     * @param password the password to set
     */
    public void setPassword(String password) {
        this.password = password;
    }

    /**
     * @return the profil
     */
    @ManyToOne( cascade = CascadeType.REFRESH, fetch = FetchType.EAGER )
    @JoinColumn( name = "fk_profil_id", nullable = false )
    public Profil getProfil() {
        return profil;
    }

    /**
     * @param profil the profil to set
     */
    public void setProfil(Profil profil) {
        this.profil = profil;
    }

    /* (non-Javadoc)
     * @see java.lang.Object#toString()
     */
    @Override
    public String toString() {
        return "User [id=" + id + ", firstname=" + firstname + ", lastname="
                + lastname + ", login=" + login + ", password=" + password
                + "]";
    }
}

这是Profil对象：

This is the Profil object:

package com.app.model;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;

@Entity
@Table(name="profil")
public class Profil {

    private long id;
    private String name;

    public Profil() {
    }

    /**
     * @param id
     * @param name
     */
    public Profil(long id, String name) {
        this.id = id;
        this.name = name;
    }   

    /**
     * @return the id
     */
    @Id
    @Column(name="id", unique = true, nullable = false)
    public long getId() {
        return id;
    }

    /**
     * @param id the id to set
     */
    public void setId(long id) {
        this.id = id;
    }

    /**
     * @return the name
     */
    @Column(name="name", unique = true, nullable = false)
    public String getName() {
        return name;
    }

    /**
     * @param name the name to set
     */
    public void setName(String name) {
        this.name = name;
    }

    /* (non-Javadoc)
     * @see java.lang.Object#toString()
     */
    @Override
    public String toString() {
        return "Profil [id=" + id + "]";
    }
}

这是控制器：

package com.app.web;

import java.util.HashMap;
import java.util.Map;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Controller;
import org.springframework.validation.BindingResult;
import org.springframework.web.bind.annotation.ModelAttribute;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;

import com.app.model.User;
import com.app.service.impl.ProfilService;
import com.app.service.impl.UserService;

@Controller
@RequestMapping("/users")
public class UserController {

    @Autowired
    private UserService userService;

    @Autowired
    private ProfilService profilService;

    @ModelAttribute("userForm")
    public User createForm()
    {
        return new User();
    }

    @RequestMapping(value = "/save", method = RequestMethod.POST)
    public ModelAndView saveUser ( @ModelAttribute("userForm") User user, BindingResult result ) {

        userService.addUser( user );

        return new ModelAndView ( "redirect:/users.html" );
    }

    @RequestMapping(method = RequestMethod.GET)
    public ModelAndView viewUsers() {
        Map model = new HashMap();
        model.put ( "users", userService.getUsers() );

        return new ModelAndView ( "usersView", model );
    }

    @RequestMapping(value = "/add", method = RequestMethod.GET)
    public ModelAndView addUser() {
        Map model = new HashMap();
        model.put ( "profils", profilService.getProfils() );

        return new ModelAndView ( "userAdd", model );
    }
}

这是JSP页面：

<%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c" %>
<%@ taglib uri="http://www.springframework.org/tags/form" prefix="form" %>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Add User</title>

</head>

<body>
<h1>Add User</h1>
<c:url var="viewUsersUrl" value="/users.html" />
<a href="${viewUsersUrl}">View Existing Users</a>

<br /><br />
<c:url var="saveUserUrl" value="/users/save.html" />
<form:form modelAttribute="userForm" method="POST" action="${saveUserUrl}">
    <form:label path="firstname">Firstname:</form:label>
    <form:input path="firstname"/><br />
    <form:label path="lastname">Lastname:</form:label>
    <form:input path="lastname"/><br />
    <form:label path="login">Login:</form:label>
    <form:input path="login"/><br />
    <form:label path="password">Password:</form:label>
    <form:input path="password"/><br />
    <form:select path="profil">  
        <form:option value="0" label="---- Select ----" />
        <form:options items="${profils}" itemValue="id" itemLabel="name" />   
    </form:select> 
    <input type="submit" value="Save User" />
</form:form>

</body>
</html>

例外：

SEVERE: Servlet.service() for servlet [spring] in context with path [/app] threw exception [Request processing failed; nested exception is org.springframework.dao.DataIntegrityViolationException: Column 'fk_profil_id' cannot be null; SQL [n/a]; constraint [null]; nested exception is org.hibernate.exception.ConstraintViolationException: Column 'fk_profil_id' cannot be null] with root cause
com.mysql.jdbc.exceptions.jdbc4.MySQLIntegrityConstraintViolationException: Column 'fk_profil_id' cannot be null
    at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
    at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:39)
    at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:27)
    at java.lang.reflect.Constructor.newInstance(Constructor.java:513)
    at com.mysql.jdbc.Util.handleNewInstance(Util.java:411)
    at com.mysql.jdbc.Util.getInstance(Util.java:386)
...
...
...

出现此异常是因为控制器中的user.profil为NULL。

This exception occurs because user.profil is NULL in the controller.

如果您需要更多信息，请随时询问。
顺便说一下，如果你发现错误或更好的方法，请告诉我，我刚接触春天和春天-mvc。

If you need more information, feel free to ask. And btw, if you notice something wrong or a better way to do, please tell me, I new to spring and spring-mvc.

非常感谢

推荐答案

在你的JSP页面组合框中应该有如下路径

in your JSP Page combo box should have path as below

<form:select path="profil.id">  
    <form:option value="0" label="---- Select ----" />
    <form:options items="${profils}" itemValue="id" itemLabel="name" />   
</form:select>

这将要求spring转换创建新的profil实例并附加User。

This will ask spring conversion to create new instance of profil and attach with User.

这篇关于Java - SpringMVC - 在控制器中获取参数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！