比较数组中的对象 [英] Compare objects in an array

问题描述

我有一个对象数组.

var array = [obj1, obj2, obj3, objN]

每个对象都有3个属性键，名称，描述.

every objects has 3 properties key, name, description.

如何比较这些对象是否相等，如果两个对象具有相同的键，则它们相等.

How can i compare these objects for equality, two objects are equal if they have the same key.

但是，如果有一个说四个对象，那么它们都必须具有相同的键才能相等.

But if a have lets say 4 objects they all must have the same key to be equal.

推荐答案

您可以使用

You can do that using Array.prototype.every():

every()方法测试数组中的所有元素是否通过提供的功能实现的测试. (mdn)

The every() method tests whether all elements in the array pass the test implemented by the provided function. _(mdn)

示例:

var array = [obj1, obj2, obj3, objN];
var allTheSame = array.every(function(element){
    return element.key === array[0].key;
});

请注意， Array.prototype.every() 是IE 9+.但是，在mdn页面上有一个很好的 polyfill 用于IE的较早版本.

Please note that Array.prototype.every() is IE 9+. However, there's a nice polyfill on the mdn page for older versions of IE.

如果您真的想使用for循环，可以这样做:

If you really want to use a for loop, you could do it like this:

var array = [obj1, obj2, obj3, objN];
var allTheSame = array.length == 1;

for(var i = 1; i < array.length && (array.length > 1 && allTheSame); i++){
    allTheSame = array[0].key == array[i].key;
}

尝试以下用途:

[{key:1},{key:1},{key:1}]; // true
[{key:1},{key:1},{key:2}]; // false
[{key:1},{key:2},{key:1}]; // false
[{key:1}]; // true

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