查找字符串中所有在两侧都只有一个括号的子字符串 [英] Find all the substrings in a string that only have a single bracket on both sides
问题描述
我正在尝试查找字符串的所有子字符串,该字符串的两边都只有一个括号.
I'm trying to find all the substrings in a string that only have a single bracket on both sides.
示例:'(pop((hello world))(goodbye(now))(hi)jump)'
我想获得以下列表:['(hi)', '(pop((hello world))(goodbye(now))(hi)jump)']
因为它们是唯一在两边都带有一个括号的子字符串.
(由于'(now))(hi)jump)'
之类的子字符串不完整,因此不算在内).
I would like to get this list: ['(hi)', '(pop((hello world))(goodbye(now))(hi)jump)']
because they are the only substrings that have exactly one bracket on both sides.
(substrings like '(now))(hi)jump)'
don't count because they aren't complete).
我的代码在这里:
import re
l = '(M264/M274)+(((551/882)+362/(362/551/882)+889)/((551/882)+362/(362/551/882)+889)+(241/242/275/550/551+882/889/362))'
print(re.findall(r"[^\(.](\([^\(.].*?[^\).]\))[^\).]", l))
将返回:
['(362/551/882)', '(362/551/882)']
我不确定如何使其包含(M264/M274)
.
请帮助我.
I'm not sure how to make it include (M264/M274)
.
Please assist me.
推荐答案
使用像[^\(.]
和[^\).]
这样的否定字符类,可以匹配未在字符类中列出的任何字符,并且至少需要一个字符.这部分 .*?可以匹配换行符以外的任何字符,因此也可以匹配括号.
Using a negated character class like [^\(.]
and [^\).]
match any char that is not listed in the character class and require at least a single char. This part .*? can match any char except a newline, so it can also match parenthesis.
它没有考虑到括号之间的平衡,但是,如果您要像问题中那样匹配(M264/M274)
,则可以结合使用环视功能和
It does not take balanced parenthesis into account, but if you want to match (M264/M274)
like in your question, you could use lookarounds in combination with a negated character class
(?<!\()\([^()]+\)(?!\))
部分
-
(?<!\()
负向后看,断言左侧不是(
-
\(
匹配(
-
[^()]+
匹配除(
或)
以外的任何字符
-
\)
匹配)
-
(?!\))
前瞻为负,断言右侧的内容不是`)
(?<!\()
Negative lookbehind, assert what is on the left is not(
\(
Match(
[^()]+
Match any char except(
or)
\)
Match)
(?!\))
Negative lookahead, assert what is on the right is not `)
如果要匹配2个左括号和右括号,还可以使用环顾四周,请注意,这也没有考虑均衡的括号.
If you want to match 2 opening and closing parenthesis, you can also make use of lookarounds and note that this also does not take balanced parenthesis into account.
(?<!\()\(\((?!\().*?\)\)(?<!\)..)(?!\))
部分(使用相同的机制或环顾四周,仅这次使用.*?
-
(?<!\()
负向后看,断言左侧不是(
-
\(\(
匹配((
-
(?!\))
前瞻为负,断言右侧的内容不是`) -
.*?
匹配除换行符0次以上以外的所有字符 -
\)\)
匹配))
-
(?<!\)..)
后面是负数,请断言))
之前的)
-
(?!\))
前瞻为负,断言右侧的内容不是`)
(?<!\()
Negative lookbehind, assert what is on the left is not(
\(\(
Match((
(?!\))
Negative lookahead, assert what is on the right is not `).*?
Match any char except a newline 0+ times\)\)
Match))
(?<!\)..)
Negative lookbehind, assert not a)
before))
(?!\))
Negative lookahead, assert what is on the right is not `)
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