用常量值初始化std :: array [英] Initializing a std::array with a constant value

问题描述

我需要使用恒定值初始化std::array的所有元素，就像可以使用std::vector一样.

I need to initialize all elements of a std::array with a constant value, like it can be done with std::vector.

#include <vector>
#include <array>

int main()
{
  std::vector<int> v(10, 7);    // OK
  std::array<int, 10> a(7);     // does not compile, pretty frustrating
}

有没有办法优雅地做到这一点?

Is there a way to do this elegantly?

现在我正在使用它:

std::array<int, 10> a;
for (auto & v : a)
  v = 7;

但我想避免使用显式代码进行初始化.

but I'd like to avoid using explicit code for the initialisation.

推荐答案

使用std::index_sequence，您可以这样做:

namespace detail
{
    template <typename T, std::size_t ... Is>
    constexpr std::array<T, sizeof...(Is)>
    create_array(T value, std::index_sequence<Is...>)
    {
        // cast Is to void to remove the warning: unused value
        return {{(static_cast<void>(Is), value)...}};
    }
}

template <std::size_t N, typename T>
constexpr std::array<T, N> create_array(const T& value)
{
    return detail::create_array(value, std::make_index_sequence<N>());
}

随用法

auto a = create_array<10 /*, int*/>(7); // auto is std::array<int, 10>

与std::fill解决方案相反，它处理非默认的可构造类型.

Which, contrary to std::fill solution, handle non default constructible type.

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