如何迅速使警告静音 [英] How to silence a warning in swift

问题描述

我有一段代码会生成很多警告(不推荐使用的API)

I have a piece of code which is generating lots of warnings (deprecated API)

使用clang *我可以做到

Using clang* I could do

#pragma clang diagnostic push
#pragma clang diagnostic ignored "-Wdeprecated-declarations"
    ...
#pragma clang diagnostic pop

但是，此操作无法迅速完成.

However this does not work in swift.

如何迅速做到?

注意:我不想全局禁用警告，甚至不想禁用整个文件，而只是在源代码的特定部分禁用特定警告.

Note: I don't want to disable the warning globally, nor even file wide, but just disable a specific warning in a specific part of my source code.

我看起来我的注释不够清楚:我不希望条件编译(这是假定重复项的建议答案). 我只想在不使用新API的情况下静默警告.

I looks like my note was not clear enough: I do NOT want conditional compilation (which is the proposed answer of the supposed duplicate). I just want to silence a warning WITHOUT using the new APIs.

推荐答案

从2019年开始，Xcode 11.0一直认为没有办法实现这一目标.

As of 2019, Xcode 11.0, the consensus is that there is no way to achieve that.

如果苹果添加了该功能，我将更新/编辑此答案.

I'll update/edit this answer if Apple add the feature.

将其放入WWDC 2020的愿望清单中！

Put it in your wish list for WWDC 2020 !

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