在gcc，如何静音-fpermissive警告？ [英] In gcc, how to mute the -fpermissive warning?

问题描述

我包括来自第三方库的文件，该文件引发可以降级为 -fpermissive 的警告的错误。但因为我不想污染我的编译日志与这些警告，我想完全禁用此消息。

I am including a file from a third-party library that raises an error that can be downgraded to a warning with -fpermissive. But because I do not want to "pollute" my compilation log with these warnings, I want to completely disable this messages.

到目前为止，我设置 -fpermissive 选项与诊断编译指示当包括文件时;例如：

So far, I set the -fpermissive option with a diagnostic pragma when including the file; something like:

#pragma GCC diagnostic push
#pragma GCC diagnostic warning "-fpermissive"

#include <third-party-file.h>

#pragma GCC diagnostic pop

因为gcc通常提供 和否定版本的 -f 标志，我想到忽略不允许功能：

Since gcc usually provide both a "positive" and "negative" version of the -f flags, I thought about ignoring the "no-permissive" feature:

#pragma GCC diagnostic ignored "-fno-permissive"
#include <third-party-file.h>

但是似乎没有否定版本的 fpermissive 标志（我使用gcc 4.6.3;但是即使是4.7.0版本没有它）。

But there does not seem to be a "negative" version of the -fpermissive flag (I am using gcc 4.6.3; but even the version 4.7.0 does not have it).

任何机会，我可以模仿这种行为吗？

Any chance I can mimic this behavior? Thanks!

推荐答案

这可能有点晚了，但其中一个应该做你想要的：

It's maybe a bit late for this, but one of these ought to do what you wanted:

#pragma GCC diagnostic ignored "-fpermissive"

或

#pragma GCC diagnostic ignored "-pedantic"

ignored是如何彻底压制诊断程序，以及 -fpermissive 是 -pedantic ，因为历史原因。

"ignored" is how you squelch a diagnostic entirely, and the inverse of -fpermissive is -pedantic, for historical reasons.

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