快速数组中的prepareForSegue元素 [英] prepareForSegue elements in Array in swift

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本文介绍了快速数组中的prepareForSegue元素的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有两个viewcontrller vc1和vc2.在vc1中,它是使用json解析的tableview,并显示一些名称.

I have two viewcontrller vc1 and vc2. In vc1 it is tableview parsed with json and it displays some names.

vc1:

var names: [String] = [] // Displays name (Ana, Mike, John ....)

override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
        let cell = tableView.dequeueReusableCellWithIdentifier("Cell", forIndexPath: indexPath) as! TVC

cell.lable.text = name[indexPath.row]

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {

        let someName: vc2 =  segue.destinationViewController as! vc2
        someName.nameFromVC1 = //need code here

    }


vc2:

var nameFromVC1: String!

我的目标是当表显示名称时,我单击一些名称说"Ana",我希望将"Ana"发送到vc2并放入var nameFromVC1

my goal is when table displays names, and I click some name say "Ana", I want "Ana" to be sent to vc2 and put in var nameFromVC1

推荐答案

您应该在vc 1中使用类似的东西:

You should use something like this in vc 1:

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {

    // Prepare the destination view controller with the selected name
    (segue.destinationViewController as? NameDetailViewController)?
        .prepareForName(
            names[tableView.indexPathForSelectedRow!.row]
        )
}

这在目标视图控制器中:

And this in your destination view controller:

func prepareForName(name: String) {
    self.name = name
}

这篇关于快速数组中的prepareForSegue元素的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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