如何使用 -prepareForSegue 中的属性? [英] How do I use a property in -prepareForSegue?

问题描述

这是我的代码，发布在视图 1 中:

Here is my code, posted in view1:

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
    // Make sure your segue name in storyboard is the same as this line
    if ([segue.identifier isEqualToString:@"toLevels"])
    {
        levelViewController *vc = [segue destinationViewController];

        vc.currentEnchantmentSelected = self.title;
    }
}

这不会将self.title"的值发送到levelViewController"中的变量.为什么是这样?如果我使用字符串，它会发送它.

This doesn't send the value of "self.title" to the variable in "levelViewController". Why is this? It sends it if I use a string.

编辑(levelViewController):

@synthesize enchantment = _enchantment;
- (enchantmentViewController *)enchantment
{
    if (!_enchantment){
        _enchantment = [[enchantmentViewController alloc] init];
    }
    return _enchantment;
}

@property enchantment 在头部声明.

推荐答案

所以从聊天中，问题是你在 didSelectRowAtIndexPath: 中设置了这个属性，实际上是在 之后调用 prepareForSegue:sender: 带有故事板.(当 segue 附加到表格中的单元格时)

So from the chat, the issue was that you were setting this property in didSelectRowAtIndexPath:, which is actually called after prepareForSegue:sender: with storyboards. (when the segue is attached to a cell in a table)

所以解决方案只是直接在 prepareForSegue:sender: 中完成这项工作.sender 将是被点击的单元格.如果您需要该单元格的 indexPath，您可以使用:

So the solution is just to do that work directly in prepareForSegue:sender: instead. The sender will be the cell that was tapped. And if you need the indexPath for that cell you can use:

[self.tableView indexPathForSelectedRow]

祝应用程序好运.

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